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Calculate the refractive index of diamond with respect to water and determine in which medium light travels faster.

Physics

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Step-by-step solution

6 steps

a)

i)

  1. Identify the given refractive indices.

    The refractive index of water (nwn_w) is 1.33.
    The refractive index of diamond (ndn_d) is 2.42.

  2. Relate refractive index to the speed of light.

    The speed of light in a medium is inversely proportional to its refractive index (v=cnv = \frac{c}{n}). A lower refractive index means light travels faster in that medium.

  3. Compare the refractive indices and determine where light moves faster.

    Since nw=1.33n_w = 1.33 is less than nd=2.42n_d = 2.42, light moves faster in water.

    ii)

  4. State the formula for the refractive index of diamond with respect to water.

    The refractive index of medium 2 with respect to medium 1 is given by n21=n2n1n_{21} = \frac{n_2}{n_1}.
    Here, ndiamond/water=ndiamondnwatern_{diamond/water} = \frac{n_{diamond}}{n_{water}}.

  5. Substitute the given values into the formula.

    ndiamond/water=2.421.33n_{diamond/water} = \frac{2.42}{1.33}
  6. Calculate the refractive index.

    ndiamond/water≈1.8195n_{diamond/water} \approx 1.8195

    Rounding to two decimal places, we get 1.82.

    i) Light moves faster in water.

    ii) The refractive index of diamond with respect to water is 1.82\boxed{\text{}1.82\text{}}

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