Resuelvelo

We are given the initial velocity ($v_0$), final velocity ($v_f$), and time ($t$).
$v_0 = 10\ \text{m/s}$
$v_f = 30\ \text{m/s}$
$t = 5\ \text{s}$

To find acceleration ($a$), we use the formula relating final velocity, initial velocity, acceleration, and time:
$v_f = v_0 + at$

$at = v_f - v_0$
$a = \frac{v_f - v_0}{t}$

$a = \frac{30\ \text{m/s} - 10\ \text{m/s}}{5\ \text{s}}$
$a = \frac{20\ \text{m/s}}{5\ \text{s}}$
$a = 4\ \text{m/s}^2$

The acceleration of the car is $\boxed{4\ \text{m/s}^2}$.

We have the initial velocity ($v_0$), time ($t$), and the acceleration ($a$) calculated in part a).
$v_0 = 10\ \text{m/s}$
$t = 5\ \text{s}$
$a = 4\ \text{m/s}^2$

To find the distance traveled ($d$), we can use the formula:
$d = v_0 t + \frac{1}{2}at^2$

$d = (10\ \text{m/s})(5\ \text{s}) + \frac{1}{2}(4\ \text{m/s}^2)(5\ \text{s})^2$
$d = 50\ \text{m} + \frac{1}{2}(4\ \text{m/s}^2)(25\ \text{s}^2)$
$d = 50\ \text{m} + (2\ \text{m/s}^2)(25\ \text{s}^2)$
$d = 50\ \text{m} + 50\ \text{m}$
$d = 100\ \text{m}$

The distance traveled by the car is $\boxed{100\ \text{m}}$.