Shadow of an electric pole is 15.95 m long, determine the distance of a sun.

This problem involves trigonometry to find the angle of elevation of the sun, using the height of an object and the length of its shadow.

Step 1: Identify the given information. The height of the electric pole (opposite side of the right-angled triangle) is $H = 5 \text{ m}$. The length of the shadow (adjacent side of the right-angled triangle) is $S = 15.95 \text{ m}$. We need to find the angle of elevation of the sun, $\theta$.

Step 2: Choose the appropriate trigonometric ratio. The tangent function relates the opposite side and the adjacent side of a right-angled triangle: $\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$

Step 3: Substitute the given values into the formula. $\tan(\theta) = \frac{H}{S}$ $\tan(\theta) = \frac{5 \text{ m}}{15.95 \text{ m}}$

Step 4: Calculate the value of $\tan(\theta)$ and find the angle $\theta$. $\tan(\theta) \approx 0.31348$ To find $\theta$, we take the inverse tangent (arctan) of this value: $\theta = \arctan(0.31348)$ $\theta \approx 17.4^{\circ}$

The angle of elevation of the sun is approximately $\boxed{17.4^{\circ}}$.