The density of 400cm³ of palm oil was 0.9g/cm³ before frying. If the density of the oil was 0.6g/cm³ after frying, assuming no loss of oil due to spilling, its volume was A. 360cm³ B. 600cm³ C. 240cm³ D. 800cm³

The initial volume of palm oil is $V_1 = 400 \text{ cm}^3$.
The initial density is $\rho_1 = 0.9 \text{ g/cm}^3$.
The final density is $\rho_2 = 0.6 \text{ g/cm}^3$.
Since there is no loss of oil, the mass of the oil remains constant ($m_1 = m_2$).

The formula for density is $\rho = \frac{m}{V}$, so mass $m = \rho \times V$.

Since $m_1 = m_2$, the final mass $m_2 = 360 \text{ g}$.
Using the formula $V = \frac{m}{\rho}$ for the final state:

The final volume is $600 \text{ cm}^3$.

The correct option is B.

52.
The question describes a gas law where, for a given mass of gas at constant pressure, the volume is proportional to the absolute temperature.

• Hooke's law relates to the extension of springs.
• Boyle's law states that pressure and volume are inversely proportional at constant temperature.
• Newton's law refers to laws of motion or gravitation.
• Charles's law states that for a fixed amount of gas at constant pressure, the volume is directly proportional to its absolute temperature ($V \propto T$).

Therefore, the gas is said to obey Charles's law.

The correct option is D.