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The problem describes a gas expanding at constant pressure. This indicates that Charles's Law should be used.

Physics

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Step-by-step solution

4 steps
  1. Identify the given values and the relevant gas law.

    The problem describes a gas expanding at constant pressure. This indicates that Charles's Law should be used.
    Charles's Law states that for a fixed amount of gas at constant pressure, the volume is directly proportional to its absolute temperature.
    The formula for Charles's Law is:

    V1T1=V2T2\frac{V_1}{T_1} = \frac{V_2}{T_2}

    Where:
    V1V_1 = initial volume
    T1T_1 = initial absolute temperature
    V2V_2 = final volume
    T2T_2 = final absolute temperature

    Given values:
    Initial volume, V1=3.25 dm3V_1 = 3.25 \text{ dm}^3
    Final volume, V2=9.75 dm3V_2 = 9.75 \text{ dm}^3

    We need to find the ratio of the final absolute temperature to the initial absolute temperature, which is T2T1\frac{T_2}{T_1}.

  2. Rearrange Charles's Law to solve for the required ratio.

    From the formula V1T1=V2T2\frac{V_1}{T_1} = \frac{V_2}{T_2}, we can rearrange it to find T2T1\frac{T_2}{T_1}:
    Multiply both sides by T2T_2:

    V1T2T1=V2\frac{V_1 T_2}{T_1} = V_2

    Divide both sides by V1V_1:

    T2T1=V2V1\frac{T_2}{T_1} = \frac{V_2}{V_1}
  3. Substitute the given values and calculate the ratio.

    Substitute the values of V1V_1 and V2V_2 into the rearranged formula:

    T2T1=9.75 dm33.25 dm3\frac{T_2}{T_1} = \frac{9.75 \text{ dm}^3}{3.25 \text{ dm}^3} T2T1=3.0\frac{T_2}{T_1} = 3.0
  4. Compare the calculated answer with the given options.

    The calculated ratio is 3.0.
    The given options are:
    A) 3.1
    B) 5.2
    C) 5.4
    D) 8.5

    The closest option to the calculated value of 3.0 is A) 3.1.

    The final answer is A) 3.1\boxed{\text{A) 3.1}}.

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