1 Analyze the pedigree chart and determine the phenotype and genotype of Senzo and Thuli, and explain the inheritance of colour-blindness.

Hey Egeteloo🥹🥹❤️, good to see you again. Here are the solutions to your questions: 25.1 a) Step 1: Identify Senzo in the pedigree chart. Senzo is represented by a filled square. Step 2: Refer to the key. A filled square indicates a colour-blind male. The phenotype of Senzo is: Colour-blind male b) Step 1: Identify Thuli in the pedigree chart. Thuli is a normal female. Step 2: Analyze Thuli's offspring. Thuli has a colour-blind daughter, Linda (X^dX^d), and a colour-blind son, Senzo (X^dY). Step 3: For Linda to be colour-blind (X^dX^d), she must inherit one X^d allele from her father and one X^d allele from her mother (Thuli). Step 4: Since Thuli is phenotypically normal but passed on an X^d allele, she must be a carrier. The genotype of Thuli is: X^DX^d 25.2 Linda is a colour-blind female, meaning her genotype is X^dX^d. She inherited one X^d allele from her mother, Thuli (X^DX^d), and the other X^d allele from her father (X^dY). 25.3 Colour-blindness is a sex-linked recessive disorder carried on the X chromosome. Males have only one X chromosome (XY), so if they inherit the recessive allele (X^d), they will express the disorder. Females have two X chromosomes (XX), meaning they need to inherit two copies of the recessive allele (X^dX^d) to be colour-blind. If a female inherits only one recessive allele, she is a carrier but has normal vision due to the dominant allele on her other X chromosome. This makes it statistically more likely for males to be colour-blind. 25.4 Step 1: Determine Molly's genotype. Molly is a normal female. Her mother is Thuli (X^DX^d) and her father is a colour-blind male (X^dY). Molly must have inherited X^D from her mother and X^d from her father. So, Molly's genotype is X^DX^d. Step 2: Determine the normal male's genotype. A normal male has the genotype X^DY. Step 3: Perform a genetic cross (Punnett square) between Molly (X^DX^d) and a normal male (X^DY). Parents: X^DX^d (Molly) × X^DY (Normal male) Gametes from Molly: X^D, X^d Gametes from Normal Male: X^D, Y |c|c|c| & X^D & Y \\ X^D & X^DX^D & X^DY \\ X^d & X^DX^d & X^dY \\ Possible Genotypes and Phenotypes of their children: Genotypes: 1/4 X^DX^D 1/4 X^DX^d 1/4 X^DY 1/4 X^dY Phenotypes: 1/2 Normal females (1/4 homozygous normal, 1/4 carrier) 1/4 Normal males 1/4 Colour-blind males Send me the next one 📸