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A woman with blood group A (heterozygous) and a man with blood group B (heterozygous) have children. What are the possible blood groups of their children?

Biology

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Step-by-step solution

3 steps
  1. Determine the genotypes of the parents.

    Blood group A is represented by alleles IA^A and i. Since the woman has blood group A and is heterozygous, her genotype is IA^Ai.
    Blood group B is represented by alleles IB^B and i. Since the man has blood group B and is heterozygous, his genotype is IB^Bi.

    Parental genotypes: Woman (IA^Ai) ×\times Man (IB^Bi)

  2. Construct a Punnett square to show the possible genotypes of the offspring.

    The gametes produced by the woman are IA^A and i.
    The gametes produced by the man are IB^B and i.

    GametesIAiIBIAIBIBiiIAiii\begin{array}{|c|c|c|} \hline \text{Gametes} & \text{I}^A & \text{i} \\ \hline \text{I}^B & \text{I}^A\text{I}^B & \text{I}^B\text{i} \\ \hline \text{i} & \text{I}^A\text{i} & \text{ii} \\ \hline \end{array}
  3. Determine the phenotypes corresponding to each genotype.

    • IA^AIB^B: Blood group AB
    • IB^Bi: Blood group B
    • IA^Ai: Blood group A
    • ii: Blood group O

    The possible phenotypes arising in the children are:
    Blood group A, Blood group B, Blood group AB, Blood group O\boxed{\text{Blood group A, Blood group B, Blood group AB, Blood group O}}

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