A woman with blood group A (heterozygous) and a man with blood group B (heterozygous) have children. What are the possible blood groups of their children?

Step 1: Determine the genotypes of the parents. Blood group A is represented by alleles I^A and i. Since the woman has blood group A and is heterozygous, her genotype is I^Ai. Blood group B is represented by alleles I^B and i. Since the man has blood group B and is heterozygous, his genotype is I^Bi. Parental genotypes: Woman (I^Ai) × Man (I^Bi) Step 2: Construct a Punnett square to show the possible genotypes of the offspring. The gametes produced by the woman are I^A and i. The gametes produced by the man are I^B and i. |c|c|c| Gametes & I^A & i \\ I^B & I^AI^B & I^Bi \\ i & I^Ai & ii \\ Step 3: Determine the phenotypes corresponding to each genotype. • I^AI^B: Blood group AB • I^Bi: Blood group B • I^Ai: Blood group A • ii: Blood group O The possible phenotypes arising in the children are: Blood group A, Blood group B, Blood group AB, Blood group O 3 done, 2 left today. You're making progress.