This biology question covers important biological concepts and processes. The step-by-step explanation below helps you understand the underlying mechanisms and reasoning.
ScanSolve AI Answer
Step 1: Determine the genotypes of the parents. Olga has blood group B and is heterozygous. The genotype for heterozygous blood group B is I^B i. Phillimon has blood group A and is homozygous. The genotype for homozygous blood group A is I^A I^A. Step 2: Set up a Punnett square for the cross. The gametes from Olga are I^B and i. The gametes from Phillimon are I^A and I^A. |c|c|c| Gametes & I^A & I^A \\ I^B & I^A I^B & I^A I^B \\ i & I^A i & I^A i \\ Step 3: Determine the possible genotypes of the offspring. From the Punnett square, the possible genotypes are I^A I^B and I^A i. Step 4: Determine the possible phenotypes (blood groups) of the offspring. • Genotype I^A I^B results in blood group AB (due to codominance). • Genotype I^A i results in blood group A (since I^A is dominant over i). The possible blood groups of their children are AB and A. The possible blood groups of their children are: Blood group AB Blood group A Send me the next one 📸