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Olga has blood group B and is heterozygous. Phillimon has blood group A and is homozygous. What are the possible blood groups of their children?

Biology

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Step-by-step solution

4 steps
  1. Determine the genotypes of the parents.

    Olga has blood group B and is heterozygous. The genotype for heterozygous blood group B is IBiI^B i.
    Phillimon has blood group A and is homozygous. The genotype for homozygous blood group A is IAIAI^A I^A.

  2. Set up a Punnett square for the cross.

    The gametes from Olga are IBI^B and ii.
    The gametes from Phillimon are IAI^A and IAI^A.

    GametesIAIAIBIAIBIAIBiIAiIAi\begin{array}{|c|c|c|} \hline \text{Gametes} & I^A & I^A \\ \hline I^B & I^A I^B & I^A I^B \\ \hline i & I^A i & I^A i \\ \hline \end{array}
  3. Determine the possible genotypes of the offspring.

    From the Punnett square, the possible genotypes are IAIBI^A I^B and IAiI^A i.

  4. Determine the possible phenotypes (blood groups) of the offspring.

    • Genotype IAIBI^A I^B results in blood group AB (due to codominance).
    • Genotype IAiI^A i results in blood group A (since IAI^A is dominant over ii).

    The possible blood groups of their children are AB and A.

    The possible blood groups of their children are:

    • Blood group AB
    • Blood group A
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