Analyze the provided pedigree diagram for Activity 7, determining the number of normal male offspring, the percentage of affected males, and the status of individual 2.

There are three male offspring.

All three male offspring are unshaded, meaning they are normal.
The number of normal male offspring of parents 1 and 2 is:

1.2

• Individual 1 (Generation I)
• Three male offspring of parents 1 and 2 (Generation II)
• One colour-blind male (shaded square, Generation II)
• Two male offspring of the colour-blind male and individual 4 (Generation III) Total number of males = $1 + 3 + 1 + 2 = 7$.

• There is one colour-blind male (shaded square, Generation II). Number of affected males = 1.

Percentage = $\frac{\text{Number of affected males}}{\text{Total number of males}} \times 100\%$
Percentage = $\frac{1}{7} \times 100\%$
Percentage $\approx 14.29\%$

The percentage of males in this pedigree diagram that are affected is:

1.3

a) Step 1: Identify individual 2. She is an unshaded circle, meaning she is a normal female.

She has a colour-blind son (shaded square in Generation II).

He inherited the $X^d$ allele from his mother.

a) The genotype of individual 2 is:

b) Step 1: Identify individual 5. She is a shaded circle, meaning she is a colour-blind female.

b) The genotype of individual 5 is:

1.4

• Individual 5 (colour-blind female): $X^d X^d$
• Normal male: $X^D Y$

Parents: $X^d X^d \times X^D Y$

Gametes from individual 5: $X^d$
Gametes from normal male: $X^D$, $Y$

Punnett Square:

All daughters will have the genotype $X^D X^d$.

All daughters ($X^D X^d$) carry the $X^d$ allele (for colour-blindness) but are phenotypically normal (not colour-blind) due to the presence of the dominant $X^D$ allele.
Therefore, $100\%$ of their daughters will fit this description.

The percentage of their daughters that will have an allele for colour-blindness, but will not be colour-blind is: