Analyze the provided pedigree diagram for Activity 7, determining the number of normal male offspring, the percentage of affected males, and the status of individual 2.

Here are the solutions for Activity 7: Pedigrees. 1.1 Step 1: Identify parents 1 and 2. Step 2: Identify their male offspring (squares in the second generation). There are three male offspring. Step 3: Observe their phenotypes. All three male offspring are unshaded, meaning they are normal. The number of normal male offspring of parents 1 and 2 is: 3 1.2 Step 1: Count all males in the pedigree diagram (squares). • Individual 1 (Generation I) • Three male offspring of parents 1 and 2 (Generation II) • One colour-blind male (shaded square, Generation II) • Two male offspring of the colour-blind male and individual 4 (Generation III) Total number of males = 1 + 3 + 1 + 2 = 7. Step 2: Count the affected males (colour-blind males, shaded squares). • There is one colour-blind male (shaded square, Generation II). Number of affected males = 1. Step 3: Calculate the percentage of affected males. Percentage = Number of affected malesTotal number of males × 100\% Percentage = (1)/(7) × 100\% Percentage ≈ 14.29\% The percentage of males in this pedigree diagram that are affected is: 14.29\% 1.3 a) Step 1: Identify individual 2. She is an unshaded circle, meaning she is a normal female. Step 2: Observe her offspring. She has a colour-blind son (shaded square in Generation II). Step 3: Since colour-blindness is X-linked recessive (X^d), a colour-blind son has the genotype X^d Y. He inherited the X^d allele from his mother. Step 4: Since individual 2 is phenotypically normal, she must also possess the dominant normal allele (X^D). a) The genotype of individual 2 is: X^D X^d b) Step 1: Identify individual 5. She is a shaded circle, meaning she is a colour-blind female. Step 2: For a female to be colour-blind in an X-linked recessive disorder, she must inherit two recessive alleles. b) The genotype of individual 5 is: X^d X^d 1.4 Step 1: Determine the genotypes of the parents. • Individual 5 (colour-blind female): X^d X^d • Normal male: X^D Y Step 2: Perform a genetic cross between X^d X^d and X^D Y. Parents: X^d X^d × X^D Y Gametes from individual 5: X^d Gametes from normal male: X^D, Y Punnett Square: |c|c|c| Gametes & X^D & Y \\ X^d & X^D X^d & X^d Y \\ X^d & X^D X^d & X^d Y \\ Step 3: Analyze the genotypes of the daughters. All daughters will have the genotype X^D X^d. Step 4: Determine the percentage of daughters who will have an allele for colour-blindness but will not be colour-blind. All daughters (X^D X^d) carry the X^d allele (for colour-blindness) but are phenotypically normal (not colour-blind) due to the presence of the dominant X^D allele. Therefore, 100\% of their daughters will fit this description. The percentage of their daughters that will have an allele for colour-blindness, but will not be colour-blind is: 100\% That's 2 down. 3 left today — send the next one.