This biology question covers important biological concepts and processes. The step-by-step explanation below helps you understand the underlying mechanisms and reasoning.
ScanSolve AI Answer
To calculate the genotype frequencies using the Hardy-Weinberg formula, we first need to determine the allele frequencies (p and q) from the given genotype frequencies. The given genotype frequencies are: AA = 0.6 Aa = 0.24 aa = 0.16 Step 1: Calculate the allele frequencies (p and q) from the given genotype frequencies. The frequency of the dominant allele (p) is calculated as the frequency of the homozygous dominant genotype plus half the frequency of the heterozygous genotype. p = freq(AA) + (1)/(2) freq(Aa) p = 0.6 + (1)/(2)(0.24) p = 0.6 + 0.12 p = 0.72 The frequency of the recessive allele (q) is calculated as the frequency of the homozygous recessive genotype plus half the frequency of the heterozygous genotype. q = freq(aa) + (1)/(2) freq(Aa) q = 0.16 + (1)/(2)(0.24) q = 0.16 + 0.12 q = 0.28 We can verify that p + q = 1: 0.72 + 0.28 = 1.00 Step 2: Calculate the expected genotype frequencies if the population were in Hardy-Weinberg equilibrium using the calculated allele frequencies (p=0.72 and q=0.28). According to the Hardy-Weinberg principle: The frequency of the homozygous dominant genotype (AA) is p^2: AA = p^2 = (0.72)^2 AA = 0.5184 The frequency of the heterozygous genotype (Aa) is 2pq: Aa = 2pq = 2 × 0.72 × 0.28 Aa = 0.4032 The frequency of the homozygous recessive genotype (aa) is q^2: aa = q^2 = (0.28)^2 aa = 0.0784 Step 3: State the calculated Hardy-Weinberg equilibrium genotype frequencies. The values of the genotypes calculated using the Hardy-Weinberg formula are: AA = 0.5184 Aa = 0.4032 aa = 0.0784 That's 2 down. 3 left today — send the next one.