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Question 14: The purpose of the constriction in the stem of a clinical thermometer is to

Biology

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3 parts
20

11A\text{11A}

24

0.2mol\text{0.2mol}

25

0.5cm3\text{0.5cm}^3

Step-by-step solution

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Here are the solutions to the questions:

Part 14

The purpose of the constriction in the stem of a clinical thermometer is to

The constriction in a clinical thermometer prevents the mercury from flowing back into the bulb immediately after use, allowing time for the temperature to be read accurately.

  • Answer: B. Prevent the liquid from flowing back into the bulb

Part 15

Which of the following diseases is caused by a virus?

Chickenpox is a highly contagious disease caused by the varicella-zoster virus.

  • Answer: C. Chicken pox

Part 16

The root system of a plant develops from the

The radicle is the embryonic root of a plant, which develops into the primary root system.

  • Answer: C. Radicle

Part 17

Chlorine is used in water treatment to

Chlorine is a powerful disinfectant used to kill harmful microorganisms, such as bacteria and viruses, in water.

  • Answer: C. Kill microbes in the water

Part 18

Carbon monoxide is poisonous to humans when inhaled because it

Carbon monoxide binds to hemoglobin in red blood cells much more readily than oxygen, forming carboxyhemoglobin and preventing oxygen transport to the body's tissues.

  • Answer: D. Blocks the path of oxygen with the blood

Part 19

A person suffering from constipation should takes in enough

Roughage (dietary fiber) adds bulk to stool and helps it pass through the digestive system, preventing constipation.

  • Answer: B. Roughages

Part 20

11A\text{11A}

Calculate the current passing through an electric kettle that operates at 110V110\text{V} and has an effective resistance of 10Ω10\Omega.

  1. Identify the given values and the formula.

    We are given voltage V=110VV = 110\text{V} and resistance R=10ΩR = 10\Omega. We need to find the current II.
    Ohm's Law states V=IRV = IR.

  2. Rearrange the formula to solve for current.

    I=VRI = \frac{V}{R}

  3. Substitute the values and calculate the current.

    I=110V10Ω=11AI = \frac{110\text{V}}{10\Omega} = 11\text{A}
    • Answer: A. 11A\boxed{\text{11A}}

Part 21

Inorganic components of soil includes the following except

Humus is decomposed organic matter, making it an organic component of soil, unlike mineral ions, soil water, and soil air which are inorganic.

  • Answer: C. Humus

Part 22

A chemical test for water in the laboratory is its ability to

Anhydrous copper (II) sulfate is a white solid that turns blue in the presence of water, making it a common chemical test for water.

  • Answer: D. Turns white anhydrous copper (II) sulphate blue

Part 23

A fruit with sticky covering is likely to be dispersed by

Fruits with sticky coverings are adapted to attach to the fur or feathers of animals, which then carry them to new locations for dispersal.

  • Answer: B. Mammals

Part 24

0.2mol\text{0.2mol}

How many moles of HCl are there in 7.3g7.3\text{g} of HCl?

  1. Determine the molar mass of HCl.

    Molar mass of H ≈1.0 g/mol\approx 1.0\text{ g/mol}
    Molar mass of Cl ≈35.5 g/mol\approx 35.5\text{ g/mol}
    Molar mass of HCl =1.0+35.5=36.5 g/mol= 1.0 + 35.5 = 36.5\text{ g/mol}

  2. Use the formula for moles.

    Moles=MassMolar Mass\text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}}

  3. Substitute the given mass and molar mass to calculate the moles.

    Moles=7.3g36.5 g/mol=0.2 mol\text{Moles} = \frac{7.3\text{g}}{36.5\text{ g/mol}} = 0.2\text{ mol}
    • Answer: C. 0.2mol\boxed{\text{0.2mol}}

Part 25

0.5cm3\text{0.5cm}^3

The density of a substance is 16gcm−316\text{gcm}^{-3}. Calculate its volume, if it has a mass of 8g8\text{g}.

  1. Identify the given values and the formula.

    We are given density ρ=16gcm−3\rho = 16\text{gcm}^{-3} and mass m=8gm = 8\text{g}. We need to find the volume VV.
    The formula for density is ρ=mV\rho = \frac{m}{V}.

  2. Rearrange the formula to solve for volume.

    V=mρV = \frac{m}{\rho}

  3. Substitute the values and calculate the volume.

    V=8g16gcm−3=0.5cm3V = \frac{8\text{g}}{16\text{gcm}^{-3}} = 0.5\text{cm}^3
    • Answer: A. 0.5cm3\boxed{\text{0.5cm}^3}

Part 26

Exhaled air may readily put off a burning candle because it contains a high level of

Exhaled air has a significantly higher concentration of carbon dioxide and water vapor compared to inhaled air. Carbon dioxide is a non-combustible gas that smothers the flame, and water vapor helps to cool it, both contributing to extinguishing the candle.

  • Answer: C. Carbon dioxide and Water vapour
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