Take the x-th root of both sides.

Another one Mukisa — let's solve it.

We need to solve the equation $3^x = x^9$.

Step 1: Take the $x$-th root of both sides. $3 = (x^9)^{1/x}$ $3 = x^{9/x}$

Step 2: Raise both sides to the power of $x/9$. $3^{x/9} = (x^{9/x})^{x/9}$ $3^{x/9} = x$ So, we are looking for solutions to $x = 3^{x/9}$.

Step 3: Test for integer solutions by inspection. Let's try $x=27$. Substitute $x=27$