How to solve for x

$2x = 7 - 3 \implies 2x = 4$

$x = \frac{4}{2} \implies x = 2$ * The solution is $x = 2$.

2. Quadratic Equation: $x^2 - 5x + 6 = 0$

$(x-2)(x-3) = 0$

    *   $x - 2 = 0 \implies x = 2$
    *   $x - 3 = 0 \implies x = 3$
*   The solutions are $x = 2$ and $x = 3$.

3. Equation with Square Root: $\sqrt{x+1} = 3$

$(\sqrt{x+1})^2 = 3^2 \implies x+1 = 9$

$x = 9 - 1 \implies x = 8$ * The solution is $x = 8$.