[9/18, 5:53 AM] Dad: Yes. This is a continuous uniform distribution question. Let’s go slowly and use the exact information in the picture. We are told: and We need to find � and �, then find �, �, and �. Find � and � Step 1: Remember the uniform distribution formula For �, So for �: Therefore: LaTeX a=0.6(b−a) 1 For �: Therefore: LaTeX 6−a=0.95(b−a) 2 Step 2: Subtract the two equations Equation (2) minus equation (1): Therefore: Step 3: Find � Using equation (1): Therefore: So: Step 4: Find � Since: So: Find � For a uniform distribution: We already found: Therefore: Hence the probability density function is: Find � For a uniform distribution: Substitute: So: Find � For a uniform distribution: We know: Therefore: ⭐ Final answers 🧠 Three formulas to memorise for � PDF: Mean: Variance: Important: In the photograph, the second probability looks like �. If your original question actually says something different (especially �), send me a clearer picture because that would change the calculation. [9/19, 9:44 PM] Dad: Hi l would like you to advise me and my 2 study partners on how to go about the whole night of study on Saturday as we are only left with 25 days to write our final examinations, we have noted a few topic that seems like our strong weaknesses in business enterprise and skills subject at advanced level so we would not like to go about the whole topic we just want the most trivial part of the topics that's all so l would like you as well to tell us the critical and most forgotten things on the following topics and how to go about them from 10.00p.m to 5 a m
Business/Management
ScanSolve AI Answer
Answer
1.258
5.828
Step-by-step solution
4 stepsI'm here to help with the uniform distribution question. Let's solve it step by step.
Given:
- (Equation 1)
- (Equation 2)
Rearranging the equations
From Equation 1:
Expanding gives:
Rearranging:
From Equation 2:
Expanding gives:
Rearranging:
Subtracting the two equations
Subtract Equation (3) from Equation (4):
This simplifies to:
Dividing by 0.35:
Calculating:
Finding
Using Equation (1):
Substituting from Equation (5):
Calculating:
Thus:
Finding
Using Equation (5):
Substituting from Equation (6):
Calculating:
Final Answers
Thus, the values are:
Final boxed answers:
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