A plane flies 300 kilometer on a bearing 30 degrees. It then flies 450 kilometer on a bearing 270 degrees. (a) Find the bearing and distance of the plane from its starting point. (b) Find how far north and how far west the plane from its starting point. Number two, the angle of elevation of the top of a radio mast from a point 54 meter from its base on level ground is 60 degrees. Find the height of the mast to the nearest meter. Use scale, one centimeter represents 9 meters.

Chemistry

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Step-by-step solution

8 steps

Let's solve these two problems.

: Plane Flight

Part a· 4 steps

Find the bearing and distance of the plane from its starting point.

  1. Break down each leg into North/South and East/West components.

    For a bearing θ (clockwise from North):
    North component = Distance × cos(θ)
    East component = Distance × sin(θ)

    Leg 1: 300 km on a bearing of 30°
    North₁ = 300 km × cos(30°) = 300 km × (√3 / 2) = 150√3 km
    East₁ = 300 km × sin(30°) = 300 km × (1/2) = 150 km

    Leg 2: 450 km on a bearing of 270° (due West)
    North₂ = 450 km × cos(270°) = 450 km × 0 = 0 km
    East₂ = 450 km × sin(270°) = 450 km × (-1) = -450 km (or 450 km West)

  2. Calculate the total North/South and East/West displacement.

    Total North displacement (N_total) = North₁ + North₂
    N_total = 150√3 km + 0 km = 150√3 km ≈ 259.81 km

    Total East displacement (E_total) = East₁ + East₂
    E_total = 150 km + (-450 km) = -300 km (or 300 km West)

  3. Calculate the total distance from the starting point.

    The total distance (D) is the hypotenuse of a right triangle formed by N_total and E_total.
    D = √(N_total² + E_total²)
    D = √((150√3)² + (-300)²)
    D = √( (22500 × 3) + 90000 )
    D = √( 67500 + 90000 )
    D = √(157500)
    D = 150√7 km
    D ≈ 396.9 km (to one decimal place)

  4. Calculate the bearing from the starting point.

    The plane is North (N_total is positive) and West (E_total is negative) of the starting point.
    Let α be the angle measured from the North axis towards the West.
    tan(α) = |E_total| / |N_total|
    tan(α) = 300 / (150√3) = 2 / √3
    α = arctan(2/√3) ≈ 49.1°

    The bearing is measured clockwise from North. Since the displacement is in the North-West quadrant, the bearing is 360° - α.
    Bearing = 360° - 49.1° = 310.9°

Part b· 4 steps

Find how far north and how far west the plane from its starting point.

From Step 2:
The plane is 150√3 km (or approximately 259.8 km) North of its starting point.
The plane is 300 km West of its starting point.

: Radio Mast Height

  1. Identify the trigonometric relationship.

    We have a right-angled triangle where:

    • The angle of elevation is 60°.
    • The distance from the base (adjacent side) is 54 m.
    • The height of the mast (opposite side) is what we need to find. The tangent function relates the opposite and adjacent sides: tan(angle) = Opposite / Adjacent.
  2. Substitute the known values into the formula.

    tan(60°) = Height / 54 m

  3. Solve for the height.

    Height = 54 m × tan(60°)
    Height = 54 m × √3
    Height ≈ 54 m × 1.73205
    Height ≈ 93.5287 m

  4. Round to the nearest meter.

    Height ≈ 94 m

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