This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Another one ✨Fave — let's solve it. The question describes a test where chlorine water is added to a salt solution containing chloroform, and the chloroform layer turns purple. We need to identify the anion present in the salt. Step 1: Understand the reaction of halogens with chlorine water. Chlorine (Cl_2) is a stronger oxidizing agent than bromine (Br_2) and iodine (I_2). Therefore, chlorine water can oxidize bromide ions (Br^-) to bromine and iodide ions (I^-) to iodine. Reaction with bromide: Cl_2(aq) + 2Br^-(aq) 2Cl^-(aq) + Br_2(aq) Reaction with iodide: Cl_2(aq) + 2I^-(aq) 2Cl^-(aq) + I_2(aq) Step 2: Understand the role of chloroform. Chloroform (CHCl_3) is an organic solvent that is immiscible with water. It is used to extract the non-polar halogens (Br_2 and I_2) from the aqueous solution, making their characteristic colors more visible. Step 3: Relate the observed color to the product. When bromine (Br_2) is extracted into chloroform, it typically produces an orange-brown or yellow-brown* color. When iodine (I_2) is extracted into chloroform (or other non-polar organic solvents like carbon tetrachloride or hexane), it produces a distinct purple or violet* color. Step 4: Match the observation to the correct anion. The question states that the chloroform layer turns purple. This color is characteristic of iodine (I_2) dissolved in chloroform. Since iodine is produced by the oxidation of iodide ions (I^-) by chlorine water, the salt must contain iodide ions. The final answer is D Drop the next question.