This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
a) The reaction between ethanol and ethanoic acid to produce ethyl ethanoate and water is an esterification reaction. CH_3CH_2OH (l) + CH_3COOH (l) CH_3COOCH_2CH_3 (l) + H_2O (l) b) Step 1: Calculate the molar mass of ethanol (CH_3CH_2OH). Molar mass of C = 12.0 g/mol Molar mass of H = 1.0 g/mol Molar mass of O = 16.0 g/mol M(CH_3CH_2OH) = (2 × 12.0) + (6 × 1.0) + (1 × 16.0) = 24.0 + 6.0 + 16.0 = 46.0 g/mol Step 2: Calculate the moles of ethanol. Moles of ethanol = Mass of ethanolMolar mass of ethanol = 23 g46.0 g/mol = 0.50 mol Step 3: Determine the moles of ethyl ethanoate produced. From the balanced chemical equation, 1 mole of ethanol reacts to produce 1 mole of ethyl ethanoate. Moles of ethyl ethanoate = 0.50 mol Step 4: Calculate the molar mass of ethyl ethanoate (CH_3COOCH_2CH_3 or C_4H_8O_2). M(CH_3COOCH_2CH_3) = (4 × 12.0) + (8 × 1.0) + (2 × 16.0) = 48.0 + 8.0 + 32.0 = 88.0 g/mol Step 5: Calculate the theoretical yield (mass) of ethyl ethanoate. Theoretical yield = Moles of ethyl ethanoate × Molar mass of ethyl ethanoate Theoretical yield = 0.50 mol × 88.0 g/mol = 44.0 g The theoretical yield of ethyl ethanoate is 44.0 g. c) Step 1: State the actual yield and theoretical yield. Actual yield = 33 g Theoretical yield = 44.0 g (from part b) Step 2: Calculate the percentage yield. Percentage yield = Actual yieldTheoretical yield × 100\% Percentage yield = 33 g44.0 g × 100\% = 0.75 × 100\% = 75\% The percentage yield is 75\%. d) Ethyl ethanoate belongs to the homologous series of esters.