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Classify the oxides of carbon, silicon, germanium, tin, and lead, and explain the properties of transition metals.

Chemistry

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Step-by-step solution

4 steps

Part c(i)· 3 steps

  1. Identify the formula for the oxide of each element in the +4 oxidation state.

    • Carbon: CO2\text{CO}_2
    • Silicon: SiO2\text{SiO}_2
    • Germanium: GeO2\text{GeO}_2
    • Tin: SnO2\text{SnO}_2
    • Lead: PbO2\text{PbO}_2
  2. Identify which oxides are amphoteric.

    Amphoteric oxides react with both acids and bases.

    • GeO2\text{GeO}_2, SnO2\text{SnO}_2, and PbO2\text{PbO}_2 are amphoteric.
  3. Identify which oxide is a greenhouse gas.

    • CO2\text{CO}_2 is a greenhouse gas.
    ElementOxideAmphotericA green house gas
    CCO2\text{CO}_2✓\checkmark
    SiSiO2\text{SiO}_2
    GeGeO2\text{GeO}_2✓\checkmark
    SnSnO2\text{SnO}_2✓\checkmark
    PbPbO2\text{PbO}_2✓\checkmark

Part c(ii)· 1 step

  1. Write the balanced chemical equation for the reaction of germanium tetrachloride (GeCl4\text{GeCl}_4) with water (H2O\text{H}_2\text{O}).

    Germanium tetrachloride undergoes hydrolysis to form germanium dioxide and hydrochloric acid.

    GeCl4(l)+2H2O(l)⟶GeO2(s)+4HCl(aq)\text{GeCl}_4(\text{l}) + 2\text{H}_2\text{O}(\text{l}) \longrightarrow \text{GeO}_2(\text{s}) + 4\text{HCl}(\text{aq})

Part d(i)

A transition metal is an element that has a partially filled d subshell in its atomic or ionic state.

Part d(ii)

A: form complexes
Transition metals form complexes because they have vacant d orbitals of suitable energy to accept lone pairs of electrons from ligands. They also have a high charge density and relatively small size, which attracts ligands.

B: show variable oxidation states
Transition metals show variable oxidation states because the energy levels of their (n−1)(n-1)d and ns orbitals are very close. This allows electrons from both subshells to be removed with comparable ease, leading to multiple stable oxidation states.

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