This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Alright Dalena — let's do this. Step 1: Calculate the moles of silver nitrate in 24.1 cm³ of solution. The volume of silver nitrate solution is 24.1 cm³, which is 0.0241 dm^3. The concentration is 0.1 mol dm^-3. Moles of AgNO_3 = Concentration × Volume Moles of AgNO_3 = 0.1 mol dm^-3 × 0.0241 dm^3 Moles of AgNO_3 = 0.00241 mol The moles of silver nitrate in 24.1 cm³ of solution is 0.00241 mol. Step 2: Calculate the moles of sodium chloride in 25.0 cm³ of solution. The reaction between silver nitrate and sodium chloride is: AgNO_3(aq) + NaCl(aq) → AgCl(s) + NaNO_3(aq) From the balanced equation, the mole ratio of AgNO_3 to NaCl is 1:1. Therefore, the moles of NaCl that reacted with 0.00241 mol of AgNO_3 is also 0.00241 mol. Moles of NaCl in 25.0 cm^3 = Moles of AgNO_3 Moles of NaCl in 25.0 cm^3 = 0.00241 mol The moles of sodium chloride in 25.0 cm³ of solution is 0.00241 mol. Step 3: Calculate the moles of sodium chloride in 250 cm³ of solution. The 25.0 cm³ sample of sodium chloride solution was taken from a total volume of 250 cm³ of the dilute solution. To find the total moles in 250 cm³, we scale up the moles from the 25.0 cm³ sample: Moles of NaCl in