Consider the reaction H2(g) + I2(g) <=> 2HI(g). What is the effect of increasing the pressure on this equilibrium?

May 7, 2026Chemistry

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May 7, 2026

Answer

$1 mol H_2 + 1 mol I_2 = 2 \text{ mol}$

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Here's a step-by-step solution to the questions:

QUESTION 1

a) Part 1.1: The balanced chemical equation is $\text{H}_2(g) + I_2(g) \rightleftharpoons 2\text{HI(g)}$ . To determine the effect of pressure on equilibrium, we compare the total number of moles of gaseous reactants and products. • Moles of gaseous reactants = $1 mol H_2 + 1 mol I_2 = 2 \text{ mol}$ • Moles of gaseous products = $2 mol HI = 2 \

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Quick Answer

Hey ïtß, good to see you again.
Here's a step-by-step solution to the questions: QUESTION 1 a) Part 1.1: The balanced chemical equation is H_2(g) + I_2(g) 2HI(g).
To determine the effect of pressure on equilibrium, we compare the total number of moles of gaseous reactants and products.
• Moles of gaseous reactants = 1 mol H_2 + 1 mol I_2 = 2 mol • Moles of gaseous products = $2 mol HI = 2 \.

Asked on May 7, 2026Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

ScanSolve AI AnswerAnswered on May 7, 2026

Hey ïtß, good to see you again. Here's a step-by-step solution to the questions: QUESTION 1 a) Part 1.1: The balanced chemical equation is H_2(g) + I_2(g) 2HI(g). To determine the effect of pressure on equilibrium, we compare the total number of moles of gaseous reactants and products. • Moles of gaseous reactants = 1 mol H_2 + 1 mol I_2 = 2 mol • Moles of gaseous products = $2 mol HI = 2 \