Convert 241in base 5 to base 8

Chemistry

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241 in base 5 is

Step 1: Convert the base 5 number to base 10. The number 241 in base 5 can be written in base 10 as: (2 × 5²) + (4 × 5¹) + (1 × 5⁰) = (2 × 25) + (4 × 5) + (1 × 1) = 50 + 20 + 1 = 71₁₀

Step 2: Convert the base 10 number to base 8. To convert 71₁₀ to base 8, we use division with remainder: 71 ÷ 8 = 8 remainder 7 8 ÷ 8 = 1 remainder 0 1 ÷ 8 = 0 remainder 1

Step 3: Read the remainders from bottom to top. The remainders are 1, 0, and 7.

Therefore, 241 in base 5 is 107 in base 8.

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Quick Answer

Convert the base 5 number to base 10. The number 241 in base 5 can be written in base 10 as: (2 × 5²) + (4 × 5¹) + (1 × 5⁰) = (2 × 25) + (4 × 5) + (1 × 1) = 50 + 20 + 1 = 71₁₀ Step 2: Convert the base 10 number to base 8.

Convert 241in base 5 to base 8
Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

ScanSolve AI Answer
Step 1: Convert the base 5 number to base 10. The number 241 in base 5 can be written in base 10 as: (2 × 5²) + (4 × 5¹) + (1 × 5⁰) = (2 × 25) + (4 × 5) + (1 × 1) = 50 + 20 + 1 = 71₁₀ Step 2: Convert the base 10 number to base 8. To convert 71₁₀ to base 8, we use division with remainder: 71 ÷ 8 = 8 remainder 7 8 ÷ 8 = 1 remainder 0 1 ÷ 8 = 0 remainder 1 Step 3: Read the remainders from bottom to top. The remainders are 1, 0, and 7. Therefore, 241 in base 5 is 107 in base 8.