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Copper forms the hydrated complex, [ extCu( extH2 extO)6]2+. (i) Give the name of the complex ion and draw its shape. (ii) Give the formula of the complex ion formed when a solution of EDTA is added t

Chemistry

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4. (b) Copper forms the hydrated complex, [Cu(H2O)6]2+[\text{Cu}(\text{H}_2\text{O})_6]^{2+}

  • (i) Give the name of the complex ion and draw its shape:

    • Name: Hexaaquacopper(II) ion\boxed{\text{Hexaaquacopper(II) ion}}
    • Shape: Octahedral\boxed{\text{Octahedral}} (A drawing would show a central Cu atom with six H2O\text{H}_2\text{O} ligands arranged at the vertices of an octahedron, with the overall 2+2+ charge outside square brackets.)
  • (ii) Give the formula of the complex ion formed when a solution of EDTA is added to a solution of [Cu(H2O)6]2+[\text{Cu}(\text{H}_2\text{O})_6]^{2+} EDTA is a hexadentate ligand, meaning it can form six coordinate bonds to a central metal ion. It will replace all six water ligands.

    • Formula: [Cu(EDTA)]2−\boxed{[\text{Cu}(\text{EDTA})]^{2-}}
  • (iii) Using the s p d notation, write the electronic configuration of copper in the complex ion. In the complex ion [Cu(H2O)6]2+[\text{Cu}(\text{H}_2\text{O})_6]^{2+}, copper is in the +2 oxidation state (Cu2+\text{Cu}^{2+}).

    • Atomic number of Copper (Cu) is 29.
    • Electronic configuration of neutral Cu: 1s22s22p63s23p63d104s11s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^1.
    • To form Cu2+\text{Cu}^{2+}, two electrons are removed: first from the 4s4s orbital, then from the 3d3d orbital.
    • Electronic configuration of Cu2+\text{Cu}^{2+}: 1s22s22p63s23p63d9\boxed{1s^2 2s^2 2p^6 3s^2 3p^6 3d^9}

4. (c) Carbon, silicon, germanium, tin and lead are elements of Group IV (14) of the Periodic Table.

  • (i) State the variation in structure of the elements carbon to lead. The elements of Group IV show a transition from giant covalent structures to giant metallic structures down the group. Carbon (diamond/graphite), silicon, and germanium have giant covalent structures. Tin and lead have giant metallic structures.

  • (ii) Give the name or formula of a chloride of Group IV element that is

    • A: covalent and decomposes readily at room temperature and pressure (r.t.p.).

      • Name: Lead(IV) chloride\boxed{\text{Lead(IV) chloride}}
      • Formula: PbCl4\boxed{\text{PbCl}_4} (Lead(IV) chloride is covalent but thermally unstable and decomposes readily at room temperature to PbCl2\text{PbCl}_2 and Cl2\text{Cl}_2.)
    • B: strongly reducing.


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