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Draw the condensed structure of the following compounds: 1. 2-bromo-3-chloro-4,4-dimethylpentanal, 2. 2,3-dihydroxybutanal, 3. 3-amino-2-methylpentanoic acid, 4. 4-methylhex-2-ene, 5. 2,4,6-tribromophenol
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Here are the condensed structures for the given compounds:
I) 2-bromo-3-chloro-4,4-dimethylpentane
The parent chain is pentane, which has 5 carbon atoms. There is a bromo group at C2, a chloro group at C3, and two methyl groups at C4.
II) 2,3-dihydroxybutan-1-ol
The parent chain is butane, which has 4 carbon atoms. There are three hydroxyl (-OH) groups: one at C1, one at C2, and one at C3.
III) 3-amino-2-methoxypentanoic acid
The parent chain is pentanoic acid, which has 5 carbon atoms with a carboxylic acid group (-COOH) at C1. There is an amino group (-NH) at C3 and a methoxy group (-OCH) at C2.
IV) 4-methylhex-2-ene
The parent chain is hex-2-ene, which has 6 carbon atoms with a double bond between C2 and C3. There is a methyl group (-CH) at C4.
V) 2,4,6-tribromophenol
Phenol is a benzene ring with an -OH group. The carbon bearing the -OH group is C1. There are bromo groups at positions 2, 4, and 6.
(This is a common way to represent substituted benzene rings in condensed form, indicating the number of hydrogens and substituents on the ring. A more detailed condensed structure would show the ring carbons and their attachments, but for a benzene derivative, the above is often accepted.)
Here are the final answers:
- I)
- II)
- III)
- IV)
- V)
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