During the electrolysis of Acidified water, a current of 0.3A was passed for 10 minutes. Calculate the volume of gas produced at the Anode. (Molar gas volume = 24dm03, 1Faraday = 96500c)

Katika elektrolisisi ya maji yenye asidi, gesi inayozalishwa kwenye anodi ni Oksijeni ($\text{O}_2$).
Mlinganyo wa nusu-mmenyuko kwenye anodi ni:

$$2\text{H}_2\text{O}(\text{l}) \longrightarrow \text{O}_2(\text{g}) + 4\text{H}^+(\text{aq}) + 4\text{e}^-$$

Kutoka kwenye mlinganyo, moli 4 za elektroni huzalisha moli 1 ya $\text{O}_2$.

Kutoka Step 1, moli 4 za elektroni huzalisha moli 1 ya $\text{O}_2$.

$$\text{Moli za O}_2 = \frac{\text{Moli za elektroni}}{4} = \frac{0.00559585 \text{ mol}}{4} \approx 0.00139896 \text{ mol}$$

$$\text{Ujazo wa O}_2 = \text{Moli za O}_2 \times \text{Ujazo wa moli kwa r.t.p}$$ $$\text{Ujazo wa O}_2 = 0.00139896 \text{ mol} \times 24 \text{ dm}^3/\text{mol} \approx 0.033575 \text{ dm}^3$$

Kuzungusha hadi sehemu tatu za desimali:

$$0.034 \text{ dm}^3$$