During the electrolysis of Acidified water, a current of 0.3A was passed for 10 minutes. Calculate the volume of gas produced at the Anode. (Molar gas volume = 24dm03, 1Faraday = 96500c)

Haya hapa majibu kwa swali lako:

During the electrolysis of Acidified water, a current of 0.3A was passed for 30 minutes. Calculate the volume of gas produced at the Anode. (Molar gas volume = 24dm³, 1Faraday = 96500C)

Step 1: Tambua gesi inayozalishwa kwenye anodi na uandike mlinganyo wa nusu-mmenyuko. Katika elektrolisisi ya maji yenye asidi, gesi inayozalishwa kwenye anodi ni Oksijeni ($\text{O}_2$). Mlinganyo wa nusu-mmenyuko kwenye anodi ni: $2H_2O(l) \longrightarrow O_2(g) + 4H^+(aq) + 4e^-$ Kutoka kwenye mlinganyo, moli 4 za elektroni huzalisha moli 1 ya $\text{O}_2$.

Step 2: Badilisha muda kuwa sekunde. $t = 30 min \times 60 s/min = 1800 \text{ s}$

Step 3: Hesabu jumla ya chaji (Q) iliyopita. $Q = I \times t = 0.3 A \times 1800 s = 540 \text{ C}$

Step 4: Hesabu moli za elektroni zilizopita. $\text{Moli za elektroni} = \frac{Q}{F} = \frac{540 C}{96500 C/mol} \approx 0.00559585 \text{ mol}$

Step 5: Hesabu moli za gesi ya Oksijeni ($\text{O}_2$) zilizozalishwa. Kutoka Step 1, moli 4 za elektroni huzalisha moli 1 ya $\text{O}_2$. $\text{Moli za O}_2 = \frac{Moli za elektroni}{4} = \frac{0.00559585 mol}{4} \approx 0.00139896 \text{ mol}$

Step 6: Hesabu ujazo wa gesi ya Oksijeni ($\text{O}_2$) kwa r.t.p. $\text{Ujazo wa O}_2 = Moli za O_2 \times \text{Ujazo wa moli kwa r.t.p}$ $\text{Ujazo wa O}_2 = 0.00139896 mol \times 24 dm^3/mol \approx 0.033575 dm^3$ Kuzungusha hadi sehemu tatu za desimali: $\boxed{0.034 dm^3}$

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