Electronic configuration

Chemistry

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Answer

1s22s22p63s23p64s2\text{1s}^2 \text{2s}^2 \text{2p}^6 \text{3s}^2 \text{3p}^6 \text{4s}^2

[Ar]4s2[\text{Ar}] \text{4s}^2

Step-by-step solution

4 steps

To write the electronic configuration, we need to know which element you're referring to. Please specify the element.

However, I can provide an example for Calcium (Ca) to illustrate the process, as it demonstrates the filling of the $4s$ orbital before the $3d$ orbital, a key concept in Advanced Level chemistry.

  1. Determine the number of electrons for Calcium (Ca).

    Calcium (Ca) has an atomic number (ZZ) of 20. This means a neutral calcium atom has 20 electrons.

  2. Fill the orbitals in increasing order of energy.

    • The 1s1s orbital holds 2 electrons: 1s21s^2 (Remaining: 20−2=1820 - 2 = 18)
    • The 2s2s orbital holds 2 electrons: 2s22s^2 (Remaining: 18−2=1618 - 2 = 16)
    • The 2p2p orbital holds 6 electrons: 2p62p^6 (Remaining: 16−6=1016 - 6 = 10)
    • The 3s3s orbital holds 2 electrons: 3s23s^2 (Remaining: 10−2=810 - 2 = 8)
    • The 3p3p orbital holds 6 electrons: 3p63p^6 (Remaining: 8−6=28 - 6 = 2)
    • The 4s4s orbital holds 2 electrons (before 3d3d): 4s24s^2 (Remaining: 2−2=02 - 2 = 0)
  3. Write the full spectroscopic notation.

    Combining the filled orbitals:

    1s22s22p63s23p64s21s^2 2s^2 2p^6 3s^2 3p^6 4s^2
  4. Write the noble gas shorthand notation.

    The noble gas preceding Calcium is Argon (Ar), which has an electronic configuration of 1s22s22p63s23p61s^2 2s^2 2p^6 3s^2 3p^6. We can replace this core configuration with [Ar][\text{Ar}].

    [Ar]4s2[\text{Ar}] 4s^2

    The electronic configuration of Calcium is:
    1s22s22p63s23p64s2\boxed{\text{1s}^2 \text{2s}^2 \text{2p}^6 \text{3s}^2 \text{3p}^6 \text{4s}^2} or [Ar]4s2\boxed{[\text{Ar}] \text{4s}^2}

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