This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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An element that is isoelectric with Neon has the same number of electrons as Neon. Neon (Ne) has an atomic number of 10, meaning it has 10 protons and 10 electrons in its neutral state. To find an element that is isoelectric with Neon, we look for an ion that also has 10 electrons. Fluorine (F) has an atomic number of 9. The Fluoride ion, F⁻, has gained one electron, giving it 9 + 1 = 10 electrons. Oxygen (O) has an atomic number of 8. The Oxide ion, O²⁻, has gained two electrons, giving it 8 + 2 = 10 electrons. Nitrogen (N) has an atomic number of 7. The Nitride ion, N³⁻, has gained three electrons, giving it 7 + 3 = 10 electrons. Sodium (Na) has an atomic number of 11. The Sodium ion, Na⁺, has lost one electron, giving it 11 - 1 = 10 electrons. Magnesium (Mg) has an atomic number of 12. The Magnesium ion, Mg²⁺, has lost two electrons, giving it 12 - 2 = 10 electrons. Aluminum (Al) has an atomic number of 13. The Aluminum ion, Al³⁺, has lost three electrons, giving it 13 - 3 = 10 electrons. Therefore, ions such as F⁻, O²⁻, N³⁻, Na⁺, Mg²⁺, and Al³⁺ are isoelectric with Neon.