Fifty (50)cm 3 of Sulphur IV oxide gas (SO2) diffuse through a porous plug in 80 seconds. What volume of…

Question

Fifty (50)cm 3 of Sulphur IV oxide gas (SO2) diffuse through a porous plug in 80 seconds. What volume of nitrogen IV oxide gas (NO2) will diffuse through the same plug in 10 seconds?

ScanSolve AI Tutor · Accepted Answer

Haya, nitakusaidia kutatua swali hili la kemia kwa kutumia Sheria ya Graham ya Usambazaji.

Swali:
Hamsini (50) cm³ ya gesi ya salfa IV oksidi ( $SO_2$ ) husambaa kupitia plagi yenye vinyweleo kwa sekunde 80. Ni kiasi gani cha gesi ya nitrojeni IV oksidi ( $NO_2$ ) kitasambaa kupitia plagi hiyo hiyo kwa sekunde 10?

Tunatumia Sheria ya Graham ya Usambazaji, ambayo inasema kwamba kiwango cha usambazaji wa gesi kinapingana na mzizi wa mraba wa uzito wake wa molekuli.

\frac{Rate_1}{Rate_2} = \sqrt{\frac{M_2}{M_1}}

Ambapo $Rate = \frac{Volume}{Time}$ .

Kokotoa uzito wa molekuli wa gesi zote mbili.
Uzito wa molekuli wa salfa IV oksidi ( $SO_2$ ): $M_{SO_2} = 32 + (2 \times 16) = 32 + 32 = 64\, \text{g/mol}$ .
Uzito wa molekuli wa nitrojeni IV oksidi ( $NO_2$ ): $M_{NO_2} = 14 + (2 \times 16) = 14 + 32 = 46\, \text{g/mol}$ .
Kokotoa kiwango cha usambazaji wa $SO_2$ .
$Rate_{SO_2} = \frac{50\, \text{cm}^3}{80\, \text{s}} = 0.625\, \text{cm}^3/\text{s}$
Tumia Sheria ya Graham kuhesabu kiwango cha usambazaji wa $NO_2$ .
$\frac{Rate_{SO_2}}{Rate_{NO_2}} = \sqrt{\frac{M_{NO_2}}{M_{SO_2}}}$ $\frac{0.625\, \text{cm}^3/\text{s}}{Rate_{NO_2}} = \sqrt{\frac{46\, \text{g/mol}}{64\, \text{g/mol}}}$ $\frac{0.625}{Rate_{NO_2}} = \sqrt{0.71875}$ $\frac{0.625}{Rate_{NO_2}} \approx 0.84779$ $Rate_{NO_2} = \frac{0.625}{0.84779} \approx 0.73720\, \text{cm}^3/\text{s}$
Kokotoa kiasi cha $NO_2$ kitakachosambaa kwa sekunde 10.
$\text{Kiasi}_{NO_2} = Rate_{NO_2} \times Time$ $\text{Kiasi}_{NO_2} = 0.73720\, \text{cm}^3/\text{s} \times 10\, \text{s}$ $\text{Kiasi}_{NO_2} \approx 7.372\, \text{cm}^3$
Kiasi cha $NO_2$ kitakachosambaa ni takriban $\boxed{\text{7.4\, cm}^3}$ .

Fifty (50)cm 3 of Sulphur IV oxide gas (SO2) diffuse through a porous plug in 80 seconds. What volume of nitrogen IV oxide gas (NO2) will diffuse through the same plug in 10 seconds?

Step-by-step solution

Kokotoa uzito wa molekuli wa gesi zote mbili.

Kokotoa kiwango cha usambazaji wa $SO_2$ .

Tumia Sheria ya Graham kuhesabu kiwango cha usambazaji wa $NO_2$ .

Kokotoa kiasi cha $NO_2$ kitakachosambaa kwa sekunde 10.

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More Chemistry Questions

Fifty (50)cm 3 of Sulphur IV oxide gas (SO2) diffuse through a porous plug in 80 seconds. What volume of nitrogen IV oxide gas (NO2) will diffuse through the same plug in 10 seconds?

Step-by-step solution

Kokotoa uzito wa molekuli wa gesi zote mbili.

Kokotoa kiwango cha usambazaji wa SO2SO_2SO2​.

Tumia Sheria ya Graham kuhesabu kiwango cha usambazaji wa NO2NO_2NO2​.

Kokotoa kiasi cha NO2NO_2NO2​ kitakachosambaa kwa sekunde 10.

Still stuck on this one?

More Chemistry Questions

Kokotoa kiwango cha usambazaji wa $SO_2$ .

Tumia Sheria ya Graham kuhesabu kiwango cha usambazaji wa $NO_2$ .

Kokotoa kiasi cha $NO_2$ kitakachosambaa kwa sekunde 10.