This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Welcome back Mazel — missed you this week. Here's the solution to the chemistry problem. The problem asks for the volume of carbon dioxide produced from 2100 kg of sodium hydrogen carbonate. The reaction is given as: 2NaHCO_3(s) heat Na_2CO_3(s) + CO_2(g) + H_2O(g) We are given the relative atomic masses: Na=23, H=1, C=12, O=16. We need to find the volume of CO_2 at STP (Standard Temperature and Pressure). At STP, 1 mole of any gas occupies 22.4 dm^3. Step 1: Calculate the molar mass of NaHCO_3. Molar mass of NaHCO_3 = (23 × 1) + (1 × 1) + (12 × 1) + (16 × 3) = 23 + 1 + 12 + 48 = 84 g/mol Step 2: Convert the mass of NaHCO_3 from kg to g and then to moles. Given mass of NaHCO_3 = 2100 kg = 2100 × 1000 g = 2.1 × 10^6 g Moles of NaHCO_3 = MassMolar mass = 2.1 × 10^6 g84 g/mol = 25000 mol Step 3: Use the stoichiometry of the reaction to find the moles of CO_2 produced. From the balanced equation, 2 moles of NaHCO_3 produce 1 mole of CO_2. Moles of CO_2 = Moles of NaHCO_3 × 1 mol CO_22 mol NaHCO_3 = 25000 mol × (1)/(2) = 12500 mol Step 4: Calculate the volume of CO_2 at STP. At STP, 1 mole of gas occupies 22.4 dm^3. Volume of CO_2 = Moles of CO_2 × 22.4 dm^3/mol = 12500 mol × 22.4 dm^3/mol = 280000 dm^3 Step 5: Convert the volume to m^3 (optional, but often preferred for large volumes). Since 1 m^3 = 1000 dm^3: Volume of CO_2 = 280000 dm^31000 dm^3/m^3 = 280 m^3 The volume of carbon dioxide produced is 280000 dm^3 or 280 m^3. Send me the next one 📸