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Given reaction: H2(g) + Br2(g) 2HBr(g) with K_p = 7.1 x 104 at 700 K.
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2 partsStep-by-step solution
4 stepsGiven reaction: with at 700 K.
Part a· 2 steps
For the reaction
Identify the relationship between the given reaction and the target reaction.
The target reaction is the reverse of the original reaction.
Calculate the new .
When a reaction is reversed, the new equilibrium constant is the reciprocal of the original equilibrium constant.
The value of is .
Part b
For the reaction
Identify the relationship between the given reaction and the target reaction.
The target reaction is the original reaction multiplied by a factor of .
Calculate the new .
When a reaction is multiplied by a factor 'n', the new equilibrium constant is the original constant raised to the power 'n'. Here, .
The value of is .
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