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Calculate [H3O^+] for each pH value using the formula [H3O^+] = 10^-pH.

Chemistry

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1. Which solution has a higher [H3O+][\text{H}_3\text{O}^+] concentration, one with pH=5\text{pH}=5, or with pH=8\text{pH}=8?

  1. Calculate [H3O+][\text{H}_3\text{O}^+] for each pH\text{pH} value using the formula [H3O+]=10−pH[\text{H}_3\text{O}^+] = 10^{-\text{pH}}.

    For pH=5\text{pH}=5:

    [H3O+]=10−5 M[\text{H}_3\text{O}^+] = 10^{-5} \text{ M}

    For pH=8\text{pH}=8:

    [H3O+]=10−8 M[\text{H}_3\text{O}^+] = 10^{-8} \text{ M}
  2. Compare the concentrations.

    Since 10−5>10−810^{-5} > 10^{-8}, the solution with pH=5\text{pH}=5 has a higher [H3O+][\text{H}_3\text{O}^+] concentration.
    Answer: The solution with pH=5\text{pH}=5 has a higher [H3O+][\text{H}_3\text{O}^+] concentration.

    2. Which solution has the higher OH−\text{OH}^- concentration?

  3. Calculate pOH\text{pOH} for each pH\text{pH} value using the formula pOH=14−pH\text{pOH} = 14 - \text{pH}.

    For pH=5\text{pH}=5:

    pOH=14−5=9\text{pOH} = 14 - 5 = 9

    For pH=8\text{pH}=8:

    pOH=14−8=6\text{pOH} = 14 - 8 = 6
  4. Calculate [OH−][\text{OH}^-] for each pOH\text{pOH} value using the formula [OH−]=10−pOH[\text{OH}^-] = 10^{-\text{pOH}}.

    For pOH=9\text{pOH}=9:

    [OH−]=10−9 M[\text{OH}^-] = 10^{-9} \text{ M}

    For pOH=6\text{pOH}=6:

    [OH−]=10−6 M[\text{OH}^-] = 10^{-6} \text{ M}
  5. Compare the concentrations.

    Since 10−6>10−910^{-6} > 10^{-9}, the solution with pH=8\text{pH}=8 has a higher [OH−][\text{OH}^-] concentration.
    Answer: The solution with pH=8\text{pH}=8 has a higher [OH−][\text{OH}^-] concentration.

    3. Give the pH\text{pH} and pOH\text{pOH} for each solution with the following concentrations:

    a) [H3O+]=1.0×10−3[\text{H}_3\text{O}^+] = 1.0 \times 10^{-3}

  6. Calculate pH\text{pH} using the formula pH=−log⁡[H3O+]\text{pH} = -\log[\text{H}_3\text{O}^+].

    pH=−log⁡(1.0×10−3)=3.0\text{pH} = -\log(1.0 \times 10^{-3}) = 3.0
  7. Calculate pOH\text{pOH} using the formula pOH=14−pH\text{pOH} = 14 - \text{pH}.

    pOH=14−3.0=11.0\text{pOH} = 14 - 3.0 = 11.0

    Answer: pH=3.0,pOH=11.0\boxed{\text{pH} = 3.0, \text{pOH} = 11.0}

    b) [OH−]=1.0×10−9 M[\text{OH}^-] = 1.0 \times 10^{-9} \text{ M}

  8. Calculate pOH\text{pOH} using the formula pOH=−log⁡[OH−]\text{pOH} = -\log[\text{OH}^-].

    pOH=−log⁡(1.0×10−9)=9.0\text{pOH} = -\log(1.0 \times 10^{-9}) = 9.0
  9. Calculate pH\text{pH} using the formula pH=14−pOH\text{pH} = 14 - \text{pOH}.

    pH=14−9.0=5.0\text{pH} = 14 - 9.0 = 5.0

    Answer: pH=5.0,pOH=9.0\boxed{\text{pH} = 5.0, \text{pOH} = 9.0}

    4. Give the hydroxide ion concentrations of solutions with the following values of pH\text{pH}:

    a) pH 13.0\text{pH } 13.0

  10. Calculate pOH\text{pOH} using the formula pOH=14−pH\text{pOH} = 14 - \text{pH}.

    pOH=14−13.0=1.0\text{pOH} = 14 - 13.0 = 1.0
  11. Calculate [OH−][\text{OH}^-] using the formula [OH−]=10−pOH[\text{OH}^-] = 10^{-\text{pOH}}.

    [OH−]=10−1.0 M=0.1 M[\text{OH}^-] = 10^{-1.0} \text{ M} = 0.1 \text{ M}

    Answer: [OH−]=0.1 M\boxed{[\text{OH}^-] = 0.1 \text{ M}}

    b) pH 3.0\text{pH } 3.0

  12. Calculate pOH\text{pOH} using the formula pOH=14−pH\text{pOH} = 14 - \text{pH}.

    pOH=14−3.0=11.0\text{pOH} = 14 - 3.0 = 11.0
  13. Calculate [OH−][\text{OH}^-] using the formula [OH−]=10−pOH[\text{OH}^-] = 10^{-\text{pOH}}.

    [OH−]=10−11.0 M[\text{OH}^-] = 10^{-11.0} \text{ M}

    Answer: [OH−]=10−11.0 M\boxed{[\text{OH}^-] = 10^{-11.0} \text{ M}}

    c) pH 8.0\text{pH } 8.0

  14. Calculate pOH\text{pOH} using the formula pOH=14−pH\text{pOH} = 14 - \text{pH}.

    pOH=14−8.0=6.0\text{pOH} = 14 - 8.0 = 6.0
  15. Calculate [OH−][\text{OH}^-] using the formula [OH−]=10−pOH[\text{OH}^-] = 10^{-\text{pOH}}.

    [OH−]=10−6.0 M[\text{OH}^-] = 10^{-6.0} \text{ M}

    Answer: [OH−]=10−6.0 M\boxed{[\text{OH}^-] = 10^{-6.0} \text{ M}}

    5. Which of the solutions is most acidic? Which is most basic? (Referring to the solutions from part 4: pH 13.0\text{pH } 13.0, pH 3.0\text{pH } 3.0, pH 8.0\text{pH } 8.0)

    • Acidity increases as pH\text{pH} decreases. The lowest pH\text{pH} among 13.0, 3.0, and 8.0 is 3.0.
    • Basicity increases as pH\text{pH} increases. The highest pH\text{pH} among 13.0, 3.0, and 8.0 is 13.0. Answer: The solution with pH=3.0\text{pH}=3.0 is most acidic. The solution with pH=13.0\text{pH}=13.0 is most basic.
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