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Identify the longest carbon chain containing the double bond.

Chemistry

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13 steps

Here are the names for the given compounds:

Part a· 3 steps

H3C−CH=CH−CH3\text{H}_3\text{C} - \text{CH} = \text{CH} - \text{CH}_3

  1. Identify the longest carbon chain containing the double bond.

    The chain has 4 carbon atoms, indicating a 'but-' parent chain.

  2. Number the carbon chain to give the double bond the lowest possible number.

    Numbering from left or right gives the double bond between C2 and C3.

  3. Name the compound.

    It is an alkene with a double bond at position 2.

    • The name is But-2-ene.

Part b· 3 steps

H2C=CH−CH2−CH3\text{H}_2\text{C} = \text{CH} - \text{CH}_2 - \text{CH}_3

  1. Identify the longest carbon chain containing the double bond.

    The chain has 4 carbon atoms, indicating a 'but-' parent chain.

  2. Number the carbon chain to give the double bond the lowest possible number.

    Numbering from left gives the double bond between C1 and C2.

  3. Name the compound.

    It is an alkene with a double bond at position 1.

    • The name is But-1-ene.

Part c· 3 steps

H2C=CH−CH=CH2\text{H}_2\text{C} = \text{CH} - \text{CH} = \text{CH}_2

  1. Identify the longest carbon chain containing both double bonds.

    The chain has 4 carbon atoms, indicating a 'buta-' parent chain (since there are two double bonds).

  2. Number the carbon chain to give the double bonds the lowest possible numbers.

    Numbering from left or right gives double bonds at C1 and C3.

  3. Name the compound.

    It is a diene with double bonds at positions 1 and 3.

    • The name is Buta-1,3-diene.

Part d· 4 steps

H2C=CH−CBr−CH3\text{H}_2\text{C} = \text{CH} - \text{CBr} - \text{CH}_3

  1. Interpret the condensed structural formula.

    The structure H2C=CH−CBr−CH3\text{H}_2\text{C} = \text{CH} - \text{CBr} - \text{CH}_3 implies that the bromine atom is attached to the third carbon in the chain, which also has a hydrogen atom to satisfy valency, making it CH2=CH−CHBr−CH3\text{CH}_2=\text{CH}-\text{CHBr}-\text{CH}_3.

  2. Identify the longest carbon chain containing the double bond.

    The chain has 4 carbon atoms, indicating a 'but-' parent chain.

  3. Number the carbon chain to give the double bond the lowest possible number and the substituent the lowest possible number.

    Numbering from the left gives the double bond at C1 and the bromine at C3.

  4. Name the compound.

    It is an alkene with a bromine substituent at position 3 and a double bond at position 1.

    • The name is 3-bromobut-1-ene.
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