Identify the solution that would have a pH value equal to a.7 b.14

Chemistry

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Question 1: Identify the solution that would have a pH value equal to 7.

A solution with a pH value of 7 is considered neutral. Examples include:

  • Pure water at 25∘C25^\circ\text{C}.
  • A solution of a salt formed from a strong acid and a strong base, such as sodium chloride (\ceNaCl\ce{NaCl}) or potassium nitrate (\ceKNO3\ce{KNO3}) dissolved in water.

Question 2: Identify the solution that would have a pH value equal to 14.

A solution with a pH value of 14 is extremely basic (alkaline). An example is:

  • A 1.0 M solution of a strong monohydroxide base, such as sodium hydroxide (\ceNaOH\ce{NaOH}) or potassium hydroxide (\ceKOH\ce{KOH}).
    • Step 1: Calculate pOH for a 1.0 M strong base. For a strong base like \ceNaOH\ce{NaOH}, it dissociates completely: \ceNaOH(aq)−>Na+(aq)+OH−(aq)\ce{NaOH(aq) -> Na+(aq) + OH-(aq)}. If [\ceNaOH]=1.0 M[\ce{NaOH}] = 1.0\ \text{M}, then [\ceOH−]=1.0 M[\ce{OH-}] = 1.0\ \text{M}. pOH=−log⁡[\ceOH−]\text{pOH} = -\log[\ce{OH-}] pOH=−log⁡(1.0)\text{pOH} = -\log(1.0) pOH=0\text{pOH} = 0
    • Step 2: Calculate pH from pOH. At 25∘C25^\circ\text{C}, pH+pOH=14\text{pH} + \text{pOH} = 14. pH=14−pOH\text{pH} = 14 - \text{pOH} pH=14−0\text{pH} = 14 - 0 pH=14\text{pH} = \boxed{14}
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