Calculate the logarithm (base 10) of 0.1279.

$$\log_{10}(0.1279) \approx -0.8931$$

The logarithm of 0.1279 is $\boxed{-0.8931}$.

$$\log_{10}(0.09545) \approx -1.0203$$

The logarithm of 0.09545 is $\boxed{-1.0203}$.

$$\log_{10}(0.009811) \approx -2.0083$$

The logarithm of 0.009811 is $\boxed{-2.0083}$.

$$\log_{10}(0.0006138) \approx -3.2119$$

The logarithm of 0.0006138 is $\boxed{-3.2119}$.