Calculate the logarithm (base 10) of 0.1279.
This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Here are the logarithms of the given numbers:
i) For $0.1279$:
Step 1: Calculate the logarithm (base 10) of $0.1279$.
$$ \log_{10}(0.1279) \approx -0.8931 $$
The logarithm of $0.1279$ is $\boxed{-0.8931}$.
ii) For $0.09545$:
Step 1: Calculate the logarithm (base 10) of $0.09545$.
$$ \log_{10}(0.09545) \approx -1.0203 $$
The logarithm of $0.09545$ is $\boxed{-1.0203}$.
iii) For $0.009811$:
Step 1: Calculate the logarithm (base 10) of $0.009811$.
$$ \log_{10}(0.009811) \approx -2.0083 $$
The logarithm of $0.009811$ is $\boxed{-2.0083}$.
iv) For $0.0006138$:
Step 1: Calculate the logarithm (base 10) of $0.0006138$.
$$ \log_{10}(0.0006138) \approx -3.2119 $$
The logarithm of $0.0006138$ is $\boxed{-3.2119}$.
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