This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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You're on a roll — Partie 1: Le paracétamol en pharmacologie Question 1: Calculer la masse molaire M du paracétamol (C_8H_9NO_2). Step 1: Use the atomic masses provided: M(C) = 12 g/mol, M(H) = 1 g/mol, M(N) = 14 g/mol, M(O) = 16 g/mol. Step 2: Calculate the molar mass of paracetamol. M(C_8H_9NO_2) = (8 × M(C)) + (9 × M(H)) + (1 × M(N)) + (2 × M(O)) M(C_8H_9NO_2) = (8 × 12) + (9 × 1) + (1 × 14) + (2 × 16) M(C_8H_9NO_2) = 96 + 9 + 14 + 32 M(C_8H_9NO_2) = 151 g/mol The molar mass of paracetamol is 151 g/mol. Question 2: Calculer la quantité de matière n (en moles) de paracétamol dans un comprimé. Step 1: Use the mass of paracetamol in one tablet m = 0.5 g and the molar mass M = 151 g/mol. Step 2: Calculate the quantity of matter. n = (m)/(M) n = 0.5 g151 g/mol n ≈ 0.00331 mol The quantity of matter is 0.00331 mol. Question 3: Combien y a-t-il de molécules de paracétamol dans un comprimé? Step 1: Use the quantity of matter n ≈ 0.00331 mol and Avogadro's number N_A = 6.02 × 10^23 mol^-1. Step 2: Calculate the number of molecules. Nombre de molécules = n × N_A Nombre de molécules = 0.00331 mol × (6.02 × 10^23 molécules/mol) Nombre de molécules ≈ 1.99 × 10^21 molécules The number of paracetamol molecules is 1.99 × 10^21 molécules. Partie 2: Le butane dans une bouteille de gaz Question 1: Déterminer la masse molaire du butane M(C_4H_10). Step 1: Use the atomic masses: M(C) = 12 g/mol, M(H) = 1 g/mol. Step 2: Calculate the molar mass of butane. M(C_4H_10) = (4 × M(C)) + (10 × M(H)) M(C_4H_10) = (4 × 12) + (10 × 1) M(C_4H_10) = 48 + 10 M(C_4H_10) = 58 g/mol The molar mass of butane is 58 g/mol. Question 2: Calculer la quantité de matière n du butane dans la bouteille. Step 1: Use the volume of the bottle V = 25 L and the molar volume of gas V_m = 24 L/mol. Step 2: Calculate the quantity of matter. n = (V)/(V_m) n = 25 L24 L/mol n ≈ 1.04 mol The quantity of matter of butane is 1.04 mol. Question 3: Quelle est la masse m du gaz contenu dans la bouteille? Step 1: Use the quantity of matter n ≈ 1.04 mol and the molar mass M = 58 g/mol. Step 2: Calculate the mass of the gas. m = n × M m = 1.04 mol × 58 g/mol m ≈ 60.32 g The mass of the butane gas is 60.32 g. Question 4: En déduire la masse volumique du butane dans ces conditions. Step 1: Use the mass of the gas m ≈ 60.32 g and the volume of the bottle V = 25 L. Step 2: Calculate the volumetric mass (density). = (m)/(V) = 60.32 g25 L ≈ 2.41 g/L The volumetric mass of butane is 2.41 g/L. Question 5: Calculer la densité d du butane par rapport à l'air. Step 1: The density of a gas relative to air can be calculated using the ratio of their molar masses, assuming ideal gas behavior at the same temperature and pressure. The average molar mass of air is approximately M_air ≈ 29 g/mol. Step 2: Calculate the density relative to air. d = M(butane)M(air) d = 58 g/mol29 g/mol d = 2 The density of butane relative to air is 2. Got more? Send 'em 📸