Here are the solutions to the problems from the image.
To solve these problems, we will use the following atomic masses:
- Strontium (Sr): 87.62 g/mol
- Phosphorus (P): 30.97 g/mol
- Oxygen (O): 16.00 g/mol
I. What is the molar mass (g/mol) of Sr3(PO4)2?
Step 1: Determine the number of atoms of each element in the compound Sr3(PO4)2.
- Strontium (Sr): 3 atoms
- Phosphorus (P): 2×1=2 atoms (from the (PO4)2 group)
- Oxygen (O): 2×4=8 atoms (from the (PO4)2 group)
Step 2: Calculate the total mass contributed by each element.
- Mass from Sr: 3×87.62g/mol=262.86 g/mol
- Mass from P: 2×30.97g/mol=61.94 g/mol
- Mass from O: 8×16.00g/mol=128.00 g/mol
Step 3: Sum the masses to find the molar mass of Sr3(PO4)2.
Molarmass=262.86g/mol+61.94g/mol+128.00g/mol
Molarmass=452.80g/mol
The molar mass of Sr3(PO4)2 is 452.80g/mol.
II. How many moles are present in 45.8 mg?
Step 1: Convert the given mass from milligrams (mg) to grams (g).
45.8mg=45.8×10−3g=0.0458g
Step 2: Use the molar mass calculated in Part I to find the number of moles.
Moles=molarmassmass
Moles=452.80g/mol0.0458g
Moles≈0.000101148mol
Moles≈1.01×10−4mol
The number of moles present is 1.01×10−4mol.
III. Determination of the percentage composition of phosphorus atom in this compound.
Step 1: Calculate the total mass of phosphorus in one mole of Sr3(PO4)2.
From Part I, there are 2 phosphorus atoms in the compound.
TotalmassofP=2×atomicmassofP
TotalmassofP=2×30.97g/mol=61.94g/mol
Step 2: Calculate the percentage composition of phosphorus using the molar mass from Part I.
PercentagecompositionofP=molarmassofSr3(PO4)2totalmassofP×100%
PercentagecompositionofP=452.80g/mol61.94g/mol×100%
PercentagecompositionofP≈0.136793×100%
PercentagecompositionofP≈13.68%
The percentage composition of phosphorus in Sr3(PO4)2 is 13.68%.