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Describe an experiment to determine the heat of combustion of methanol.

Chemistry

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Answer

b

−384 kJ mol−1\mathbf{-384 \text{ kJ mol}^{-1}}

Step-by-step solution

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Here's the solution to question 8:

Part a

Describe an experiment to determine the heat of combustion of methanol.

  • Set-up:

    • A spirit lamp containing methanol is weighed and placed under a copper calorimeter.
    • The calorimeter contains a known mass of water and is suspended by a clamp.
    • A thermometer is immersed in the water to measure temperature.
    • The entire apparatus is enclosed within a draught shield (e.g., a larger tin can) to minimize heat loss to the surroundings.
    • Insulating material (e.g., cotton wool) can be placed around the calorimeter.
  • Data Collection:

    1. Record the initial mass of the spirit lamp and methanol.
    2. Record the initial temperature of the water in the calorimeter.
    3. Light the spirit lamp and allow the methanol to burn, heating the water.
    4. Stir the water continuously.
    5. After a suitable temperature rise, extinguish the flame and immediately record the highest temperature reached by the water.
    6. Record the final mass of the spirit lamp and remaining methanol.
  • Precautions:

    • Use a draught shield to prevent heat loss due to convection currents and ensure complete combustion.
    • Insulate the calorimeter to minimize heat loss to the surroundings.
    • Stir the water constantly to ensure uniform temperature distribution and accurate readings.
    • Ensure the flame is directly under the calorimeter for efficient heat transfer.
  • Assumptions:

    • All heat released by the combustion of methanol is absorbed by the water and the calorimeter.
    • The specific heat capacity of water is constant (4.2 J g−1 °C−14.2 \text{ J g}^{-1} \text{ °C}^{-1}).
    • The density of water is 1 g cm−31 \text{ g cm}^{-3}.
    • Complete combustion of methanol occurs.
    • The heat capacity of the calorimeter is negligible or accounted for.

Part b

−384 kJ mol−1\mathbf{-384 \text{ kJ mol}^{-1}}

Calculate the molar heat of combustion of methanol.

  1. Calculate the mass of water.

    Given the volume of water is 100 cm3100 \text{ cm}^3 and assuming the density of water is 1 g cm−31 \text{ g cm}^{-3}.

    mwater=Vwater×ρwater=100 cm3×1 g cm−3=100 gm_{water} = V_{water} \times \rho_{water} = 100 \text{ cm}^3 \times 1 \text{ g cm}^{-3} = 100 \text{ g}
  2. Calculate the temperature change of the water.

    ΔT=Tfinal−Tinitial=80 °C−20 °C=60 °C\Delta T = T_{final} - T_{initial} = 80 \text{ °C} - 20 \text{ °C} = 60 \text{ °C}
  3. Calculate the heat absorbed by the water.

    Using the formula Q=m×c×ΔTQ = m \times c \times \Delta T, where cc for water is 4.2 J g−1 °C−14.2 \text{ J g}^{-1} \text{ °C}^{-1}.

    Qwater=100 g×4.2 J g−1 °C−1×60 °CQ_{water} = 100 \text{ g} \times 4.2 \text{ J g}^{-1} \text{ °C}^{-1} \times 60 \text{ °C} Qwater=25200 J=25.2 kJQ_{water} = 25200 \text{ J} = 25.2 \text{ kJ}
  4. Calculate the moles of methanol burned.

    Given the mass of methanol is 2.1 g2.1 \text{ g} and RMM is 32 g mol−132 \text{ g mol}^{-1}.

    nmethanol=massRMM=2.1 g32 g mol−1=0.065625 moln_{methanol} = \frac{\text{mass}}{\text{RMM}} = \frac{2.1 \text{ g}}{32 \text{ g mol}^{-1}} = 0.065625 \text{ mol}
  5. Calculate the molar heat of combustion.

    The molar heat of combustion is the heat released per mole of methanol. Since heat was absorbed by the water, the combustion is exothermic, so the value will be negative.

    ΔHc=−Qwaternmethanol=−25.2 kJ0.065625 mol\Delta H_c = -\frac{Q_{water}}{n_{methanol}} = -\frac{25.2 \text{ kJ}}{0.065625 \text{ mol}} ΔHc=−384 kJ mol−1\Delta H_c = -384 \text{ kJ mol}^{-1}

    The molar heat of combustion of methanol is −384 kJ mol−1\boxed{\mathbf{-384 \text{ kJ mol}^{-1}}}.

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