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Which of the following ions will interact with water to give a solution of pH < 7? A.Na+ B.NH4+ C.CN- D.HCOO-

Chemistry

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Answer

B

Step-by-step solution

2 steps

To determine which ion will give a solution with pH < 7 (acidic), we need to consider the hydrolysis of each ion in water.

  1. Analyze the nature of each ion.

    • A. Na+^+: This is the conjugate acid of a strong base (NaOH). Ions from strong bases do not hydrolyze significantly in water, so they do not affect the pH.
    • B. NH4+_4^+: This is the conjugate acid of a weak base (NH3_3). Conjugate acids of weak bases are acidic and will react with water to produce H3_3O+^+ ions.
    • C. CN−^-: This is the conjugate base of a weak acid (HCN). Conjugate bases of weak acids are basic and will react with water to produce OH−^- ions.
    • D. HCOO−^-: This is the conjugate base of a weak acid (formic acid, HCOOH). Similar to CN−^-, it will react with water to produce OH−^- ions.
  2. Write the hydrolysis reaction for the ion that would produce an acidic solution.

    An acidic solution has a pH less than 7, meaning it has an excess of H3_3O+^+ ions. From Step 1, NH4+_4^+ is the only ion that is an acidic conjugate.
    The hydrolysis reaction for NH4+_4^+ is:

    NH4+(aq)+H2O(l)⇌NH3(aq)+H3O+(aq)\text{NH}_4^+ (aq) + \text{H}_2\text{O} (l) \rightleftharpoons \text{NH}_3 (aq) + \text{H}_3\text{O}^+ (aq)

    This reaction produces hydronium ions (H3O+\text{H}_3\text{O}^+), which makes the solution acidic, resulting in a pH less than 7.

    The other ions would either not affect the pH (Na+^+) or make the solution basic (CN−^- and HCOO−^-).

    The correct option is B.

    B. NH4+\boxed{\text{B. NH}_4^+}

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