Determine oxidation of sulphur in H2S04
Chemistry
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Step-by-step solution
5 stepsIdentify the elements in the compound.
The compound is sulfuric acid, H₂SO₄. The elements present are Hydrogen (H), Sulfur (S), and Oxygen (O).
Recall the common oxidation states of Hydrogen and Oxygen.
Hydrogen typically has an oxidation state of +1 when bonded to nonmetals.
Oxygen typically has an oxidation state of -2, except in peroxides or when bonded to fluorine.Set up an equation for the sum of oxidation states in a neutral compound.
The sum of the oxidation states of all atoms in a neutral compound is zero.
For H₂SO₄: (2 × oxidation state of H) + (1 × oxidation state of S) + (4 × oxidation state of O) = 0Substitute the known oxidation states into the equation.
(2 × +1) + (1 × oxidation state of S) + (4 × -2) = 0
Simplify and solve for the oxidation state of Sulfur (S).
+2 + oxidation state of S - 8 = 0
oxidation state of S - 6 = 0
oxidation state of S = +6The oxidation state of sulfur in H₂SO₄ is +6.
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