Step 1: Identify the elements in the compound. The compound is sulfuric acid, H₂SO₄. The elements present are Hydrogen (H), Sulfur (S), and Oxygen (O). Step 2: Recall the common oxidation states of Hydrogen and Oxygen. Hydrogen typically has an oxidation state of +1 when bonded to nonmetals. Oxygen typically has an oxidation state of -2, except in peroxides or when bonded to fluorine. Step 3: Set up an equation for the sum of oxidation states in a neutral compound. The sum of the oxidation states of all atoms in a neutral compound is zero. For H₂SO₄: (2 × oxidation state of H) + (1 × oxidation state of S) + (4 × oxidation state of O) = 0 Step 4: Substitute the known oxidation states into the equation. (2 × +1) + (1 × oxidation state of S) + (4 × -2) = 0 Step 5: Simplify and solve for the oxidation state of Sulfur (S). +2 + oxidation state of S - 8 = 0 oxidation state of S - 6 = 0 oxidation state of S = +6 The oxidation state of sulfur in H₂SO₄ is +6. Send me the next one 📸