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Calculate the oxidation Valency of the following: NO3, HNO3, NO3, NH+, N2O3

Chemistry

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Here are the oxidation states for the specified elements in each compound or ion:

1. For Nitrogen (N) in NO2NO_2

  1. Assign known oxidation states.

    Oxygen typically has an oxidation state of −2-2. Let the oxidation state of Nitrogen be xx.

  2. Set the sum of oxidation states equal to the overall charge of the compound.

    For a neutral compound like NO2NO_2, the overall charge is 0.

    x+2(−2)=0x + 2(-2) = 0
  3. Solve for xx.

    x−4=0x - 4 = 0 x=+4x = +4

    The oxidation state of Nitrogen in NO2NO_2 is +4\boxed{+4}.

    2. For Nitrogen (N) in HNO3HNO_3

  4. Assign known oxidation states.

    Hydrogen typically has an oxidation state of +1+1, and Oxygen typically has an oxidation state of −2-2. Let the oxidation state of Nitrogen be xx.

  5. Set the sum of oxidation states equal to the overall charge of the compound.

    For a neutral compound like HNO3HNO_3, the overall charge is 0.

    1(+1)+x+3(−2)=01(+1) + x + 3(-2) = 0
  6. Solve for xx.

    1+x−6=01 + x - 6 = 0 x−5=0x - 5 = 0 x=+5x = +5

    The oxidation state of Nitrogen in HNO3HNO_3 is +5\boxed{+5}.

    3. For Nitrogen (N) in NO3−NO_3^{-}

  7. Assign known oxidation states.

    Oxygen typically has an oxidation state of −2-2. Let the oxidation state of Nitrogen be xx.

  8. Set the sum of oxidation states equal to the overall charge of the ion.

    For the NO3−NO_3^{-} ion, the overall charge is −1-1.

    x+3(−2)=−1x + 3(-2) = -1
  9. Solve for xx.

    x−6=−1x - 6 = -1 x=−1+6x = -1 + 6 x=+5x = +5

    The oxidation state of Nitrogen in NO3−NO_3^{-} is +5\boxed{+5}.

    4. For Nitrogen (N) in NH4+NH_4^{+}

  10. Assign known oxidation states.

    Hydrogen typically has an oxidation state of +1+1. Let the oxidation state of Nitrogen be xx.

  11. Set the sum of oxidation states equal to the overall charge of the ion.

    For the NH4+NH_4^{+} ion, the overall charge is +1+1.

    x+4(+1)=+1x + 4(+1) = +1
  12. Solve for xx.

    x+4=+1x + 4 = +1 x=+1−4x = +1 - 4 x=−3x = -3

    The oxidation state of Nitrogen in NH4+NH_4^{+} is −3\boxed{-3}.

    5. For Nitrogen (N) in N2O3N_2O_3

  13. Assign known oxidation states.

    Oxygen typically has an oxidation state of −2-2. Let the oxidation state of Nitrogen be xx.

  14. Set the sum of oxidation states equal to the overall charge of the compound.

    For a neutral compound like N2O3N_2O_3, the overall charge is 0.

    2x+3(−2)=02x + 3(-2) = 0
  15. Solve for xx.

    2x−6=02x - 6 = 0 2x=62x = 6 x=62x = \frac{6}{2} x=+3x = +3

    The oxidation state of Nitrogen in N2O3N_2O_3 is +3\boxed{+3}.

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