This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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You're on a roll — Here are the answers to your questions: 5. Which particles conduct electricity in: a) Molten lead (II) bromide ✅ Correct. The particles are ions (Pb^2+ and Br^-). b) Lead metal ✅ Correct. The particles are delocalized electrons. 6. The information in the table below relates to the physical properties of the chlorides of certain elements. a) Explain why melting points of NaCl and MgCl_2 are higher than those of SiCl_4, PCl_3 and SCl_2 chlorides in the table above. NaCl and MgCl_2 are ionic compounds with strong electrostatic forces of attraction between oppositely charged ions in a giant ionic lattice structure. A large amount of energy is required to overcome these strong forces, resulting in high melting points. SiCl_4, PCl_3, and SCl_2 are covalent compounds that exist as simple discrete molecules. The forces between these molecules are weak intermolecular forces (van der Waals forces). Only a small amount of energy is required to overcome these weak forces, leading to low melting points. 7. 400 cm^3 of a gas D diffuses through a porous plug in 50 seconds, while 600 cm^3 of oxygen gas diffuses from the same apparatus in 30 seconds. Calculate the relative molecular mass of gas D. (O = 16) Step 1: Calculate the rate of diffusion for gas D and oxygen. Rate of diffusion = Volume diffusedTime taken Rate_D = 400 cm^350 s = 8 cm^3/s Rate_O_2 = 600 cm^330 s = 20 cm^3/s Step 2: Determine the relative molecular mass of oxygen gas. Relative atomic mass of O = 16. Relative molecular mass of O_2 = 2 × 16 = 32. Step 3: Apply Graham's Law of Diffusion. Graham's Law states that the rate of diffusion of a gas is inversely proportional to the square root of its relative molecular mass. (Rate_D)/(Rate_O_2) = sqrt(M_O_2)M_D Substitute the known values: (8)/(20) = sqrt((32)/(M_D)) 0.4 = sqrt((32)/(M_D)) Step 4: Square both sides of the equation. (0.4)^2 = (32)/(M_D) 0.16 = (32)/(M_D) Step 5: Solve for M_D. M_D = (32)/(0.16) M_D = 200 8. Study the flow chart below and answer the questions the follow. a) White precipitate A: Calcium carbonate (CaCO_3) b) Solution B: Calcium hydrogencarbonate (Ca(HCO_3)_2) c) Gas C: Carbon(IV) oxide (CO_2) 9. Classify the following processes as either chemical or physical. i) Heating Ammonium Chloride: Chemical change ii) Obtaining kerosene from crude oil: Physical change iii) Souring of milk: Chemical change What's next?