This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Step 1: Set up the equation for relative atomic mass. Let x be the percentage abundance of Lithium-6. Then the percentage abundance of Lithium-7 will be (100 - x). The formula for relative atomic mass (Ar) is: Ar = (mass of isotope 1 × abundance 1) + (mass of isotope 2 × abundance 2)100 Given: Ar = 6.94 Mass of Lithium-6 = 6 Mass of Lithium-7 = 7 Step 2: Substitute the given values into the formula. 6.94 = ((6 × x) + (7 × (100 - x)))/(100) Step 3: Solve for x. Multiply both sides by 100: 6.94 × 100 = 6x + 7(100 - x) 694 = 6x + 700 - 7x 694 = 700 - x Subtract 700 from both sides: 694 - 700 = -x -6 = -x x = 6 Step 4: Determine the percentage abundance of each isotope. Percentage abundance of Lithium-6 = x = 6\% Percentage abundance of Lithium-7 = 100 - x = 100 - 6 = 94\% The percentage abundance of Lithium-6 is 6\% and Lithium-7 is 94\%. --- Problem 10: Step 1: Set up the equation for relative atomic mass. The formula for relative atomic mass (Ar) is: Ar = (mass of isotope 1 × abundance 1) + (mass of isotope 2 × abundance 2)100 Given: Ar = 30 Abundance of isotope 1 = 65% Mass number of isotope 1 = x Abundance of isotope 2 = 35% Mass number of isotope 2 = 31 Step 2: Substitute the given values into the formula. 30 = ((x × 65) + (31 × 35))/(100) Step 3: Solve for x. Multiply both sides by 100: 30 × 100 = 65x + (31 × 35) 3000 = 65x + 1085 Subtract 1085 from both sides: 3000 - 1085 = 65x 1915 = 65x Divide by 65: x = (1915)/(65) x = 29.46 Since mass numbers are typically whole numbers, we can round this to the nearest whole number. x ≈ 29 The mass number represented by x is approximately 29 (or 29.46 if not rounded). Last free one today — make it count tomorrow, or type /upgrade for unlimited.