Here are the solutions to your questions:
1. Periodic Table Section
a) Using the letters from the table, select an element that is:
- i) Stored in paraffin oil.
Alkali metals (Group 1) are highly reactive and stored in paraffin oil. Element A is in Group 1.
Answer: A
- ii) A reddish liquid at RTP.
Bromine is a reddish-brown liquid at room temperature. Bromine is in Group 17, Period 4. The elements F (Group 17, Period 2) and G (Group 17, Period 3) are not Bromine. None of the elements A-H shown in the table fit this description.
Answer: None of the elements shown
b) Write the electronic configuration of:
- i) B:
Element B is in Group 2, Period 2. This corresponds to Beryllium (Be), which has an atomic number of 4.
Electronic configuration: 2,2 (or 1s22s2)
- ii) Why is B classified in group II?
Element B is classified in Group II because it has twovalenceelectrons (two electrons in its outermost electron shell).
c) The element, E, has a relative atomic mass of 27. Give the composition of an atom of E.
If the relative atomic mass of element E is 27, then E is Aluminum (Al). Aluminum has an atomic number of 13.
- i) Number of protons: The atomic number equals the number of protons.
Answer: 13
- ii) Number of electrons: For a neutral atom, the number of electrons equals the number of protons.
Answer: 13
- iii) Number of neutrons: The number of neutrons is calculated by subtracting the number of protons from the relative atomic mass.
Numberofneutrons=Relativeatomicmass−Numberofprotons
Numberofneutrons=27−13=14
Answer: 14
d) Two elements X and Y have atomic numbers of 6 and 17 respectively.
- Element X (atomic number 6) is Carbon (C).
- Element Y (atomic number 17) is Chlorine (Cl).
- i) Write the formula of the compound formed between X and Y.
Carbon (Group 14) typically forms 4 covalent bonds. Chlorine (Group 17) typically forms 1 covalent bond. To satisfy the valencies, one carbon atom will bond with four chlorine atoms.
Formula: CCl4
- ii) Identify the bond type in the compound in d(i) above.
Carbon and Chlorine are both non-metals. The bond formed between two non-metals is a covalent bond.
Bond type: Covalentbond
e) Sodium chloride has the formula NaCl. Identify the charge of the metallic ion:
In Sodium chloride (NaCl), Sodium (Na) is the metallic ion. Sodium is in Group 1 and loses one electron to form a stable ion.
Charge of the metallic ion: +1 (or Na+)
2. Elements and Reactions
Given elements: Sodium (Na), Silver (Ag), Calcium (Ca), Iron (Fe), Aluminium (Al).
a) Select from the elements:
- i) A transition metal used as a catalyst.
Iron (Fe) is a transition metal commonly used as a catalyst (e.g., in the Haber process).
Answer: Iron(Fe)
- ii) An element that forms an amphoteric oxide.
Amphoteric oxides react with both acids and bases. Aluminium (Al) forms an amphoteric oxide (Al2O3).
Answer: Aluminium(Al)
- iii) An element that is a basic constituent of bones.
Calcium (Ca) is a major component of bones, primarily in the form of calcium phosphate.
Answer: Calcium(Ca)
b) Arrange the elements in order of decreasing reactivity, starting from the most reactive.
Based on the reactivity series, the order from most reactive to least reactive is:
Order: Sodium(Na),Calcium(Ca),Aluminium(Al),Iron(Fe),Silver(Ag)
c) The element Calcium (Ca) reacts with dilute hydrochloric acid.
- i) State one common observation.
Calcium is a reactive metal that reacts with acids to produce hydrogen gas.
Observation: Effervescence(fizzingorbubbling)
- ii) Write a balanced equation for the reaction taking place.
Calcium reacts with hydrochloric acid to form calcium chloride and hydrogen gas.
Ca(s)+2HCl(aq)→CaCl2(aq)+H2(g)
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