Q6. Name this compound

The image shows a skeletal structure. Each vertex and the end of a line represents a carbon atom. Hydrogens are implied to satisfy carbon's valency of 4.
Let's trace the carbons:
There are two central carbon atoms connected by a bond. Let's call them C1 and C2.
From C1, there are two branches (methyl groups).
From C2, there are two branches (methyl groups).
So, the structure is:

      CH3   CH3
      |     |
CH3 - C1 --- C2 - CH3
      |     |
      CH3   CH3

Let's find the longest continuous carbon chain.
If we start from one of the methyl groups attached to C1, go through C1, C2, and then to one of the methyl groups attached to C2, we get a 4-carbon chain. For example:
$\text{CH}_3 - \text{C}1 - \text{C}2 - \text{CH}_3$
This is a butane chain.

The parent chain is butane (4 carbons).
Let's number it:
$\text{C}1\text{H}_3 - \text{C}2(\text{CH}_3)_2 - \text{C}3(\text{CH}_3)_2 - \text{C}4\text{H}_3$
From either end, the substituents are at positions 2 and 3.

At carbon 2, there are two methyl ($\text{CH}_3$) groups.
At carbon 3, there are two methyl ($\text{CH}_3$) groups.
In total, there are four methyl groups.

The parent chain is butane.
There are four methyl groups, so we use the prefix "tetra-".
The positions of the methyl groups are 2, 2, 3, 3.
Combining these, the name is 2,2,3,3-tetramethylbutane.

Now, let's compare this with the given options:
A. 2,2,3-trimethyl propane
B. 2,2,3-trimethyl pentane

There is a discrepancy. The compound shown in the image is 2,2,3,3-tetramethylbutane, which has 8 carbon atoms (4 in the main chain + 4 in the methyl groups).
Let's analyze the options:

• A. 2,2,3-trimethyl propane: A propane chain has 3 carbons. "Trimethyl" means 3 methyl groups. So, this compound would have $3 + 3 = 6$ carbons. However, "2,2,3-trimethyl propane" is an invalid IUPAC name because the longest continuous carbon chain would actually be 4 carbons (butane), making it 2,2,3-trimethylbutane (7 carbons).
• B. 2,2,3-trimethyl pentane: A pentane chain has 5 carbons. "Trimethyl" means 3 methyl groups. So, this compound would have $5 + 3 = 8$ carbons.

Given that the image represents 2,2,3,3-tetramethylbutane (8 carbons), and option B (2,2,3-trimethyl pentane) also has 8 carbons, it is possible that the question intends for the image to represent 2,2,3-trimethyl pentane, despite the drawing's symmetry suggesting 2,2,3,3-tetramethylbutane. However, based on standard interpretation of skeletal structures, the image clearly depicts 2,2,3,3-tetramethylbutane.

If we strictly follow the IUPAC rules for the drawn structure, the name is 2,2,3,3-tetramethylbutane. Since this is not an option, there might be an error in the question or the options provided.

However, if forced to choose the closest option based on the number of carbons and the general structure (highly branched alkane), option B (2,2,3-trimethyl pentane) has 8 carbons, which is the same total number of carbons as 2,2,3,3-tetramethylbutane. The branching pattern is different, but it's the only option with the correct total carbon count.

Assuming there might be a slight misrepresentation in the drawing and that one of the options is correct, we choose the option that matches the total number of carbons.

The compound 2,2,3-trimethyl pentane has the following structure:

      CH3
      |
CH3 - C - CH - CH2 - CH3
      |   |
      CH3 CH3

This compound has 8 carbons. The image, as drawn, also has 8 carbons (2 central + 6 branches).
While the specific branching pattern in the image (two methyls on each central carbon) is more consistent with 2,2,3,3-tetramethylbutane, if we must select from the given choices, and considering the total carbon count, option B is the most plausible.

The final answer is $\boxed{\text{B. 2,2,3-trimethyl pentane}}$.