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Chemistry

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Here is a science problem from Chemistry:

Problem: Balance the following chemical equation:
CH4(g)+O2(g)→CO2(g)+H2O(g)\text{CH}_4(\text{g}) + \text{O}_2(\text{g}) \rightarrow \text{CO}_2(\text{g}) + \text{H}_2\text{O}(\text{g})

  1. Count the atoms of each element on both sides of the equation.

    Reactants:
    C: 1
    H: 4
    O: 2

    Products:
    C: 1
    H: 2
    O: 3

  2. Balance the Carbon (C) atoms.

    The carbon atoms are already balanced (1 on each side).

  3. Balance the Hydrogen (H) atoms.

    There are 4 H atoms on the reactant side and 2 H atoms on the product side. To balance, place a coefficient of 2 in front of H2O\text{H}_2\text{O} on the product side:
    CH4(g)+O2(g)→CO2(g)+2H2O(g)\text{CH}_4(\text{g}) + \text{O}_2(\text{g}) \rightarrow \text{CO}_2(\text{g}) + 2\text{H}_2\text{O}(\text{g})

  4. Re-count atoms and balance the Oxygen (O) atoms.

    Reactants:
    C: 1
    H: 4
    O: 2

    Products:
    C: 1
    H: 2×2=42 \times 2 = 4
    O: 2(from CO2)+2(from 2H2O)=42 (\text{from } \text{CO}_2) + 2 (\text{from } 2\text{H}_2\text{O}) = 4

    Now, there are 2 O atoms on the reactant side and 4 O atoms on the product side. To balance, place a coefficient of 2 in front of O2\text{O}_2 on the reactant side:
    CH4(g)+2O2(g)→CO2(g)+2H2O(g)\text{CH}_4(\text{g}) + 2\text{O}_2(\text{g}) \rightarrow \text{CO}_2(\text{g}) + 2\text{H}_2\text{O}(\text{g})

  5. Verify that all atoms are balanced.

    Reactants:
    C: 1
    H: 4
    O: 2×2=42 \times 2 = 4

    Products:
    C: 1
    H: 2×2=42 \times 2 = 4
    O: 2(from CO2)+2(from 2H2O)=42 (\text{from } \text{CO}_2) + 2 (\text{from } 2\text{H}_2\text{O}) = 4

    All atoms are balanced.

    The balanced chemical equation is:

    CH4(g)+2O2(g)→CO2(g)+2H2O(g)\boxed{\text{CH}_4(\text{g}) + 2\text{O}_2(\text{g}) \rightarrow \text{CO}_2(\text{g}) + 2\text{H}_2\text{O}(\text{g})}
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