Write the reaction between HNO³+KOH

$\text{HNO}_3$ is nitric acid.
$\text{KOH}$ is potassium hydroxide.

The hydrogen ion ($\text{H}^+$) from the acid combines with the hydroxide ion ($\text{OH}^-$) from the base to form water ($\text{H}_2\text{O}$).
The remaining ions, potassium ($\text{K}^+$) from the base and nitrate ($\text{NO}_3^-$) from the acid, combine to form the salt, potassium nitrate ($\text{KNO}_3$).

$\text{HNO}_3 (\text{aq}) + \text{KOH} (\text{aq}) \rightarrow \text{KNO}_3 (\text{aq}) + \text{H}_2\text{O} (\text{l})$

Count the atoms on both sides:
Left side: H = 2, N = 1, O = 4, K = 1
Right side: H = 2, N = 1, O = 4, K = 1
The reaction is already balanced.

The balanced chemical reaction is: