This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Potassium hydroxide (KOH) is a strong base. Its reactions primarily involve: 1. Neutralization reactions with acids: KOH reacts with acids to form a salt and water. For example, with hydrochloric acid (HCl): KOH(aq) + HCl(aq) → KCl(aq) + H_2O(l) With sulfuric acid (H_2SO_4): 2KOH(aq) + H_2SO_4(aq) → K_2SO_4(aq) + 2H_2O(l) 2. Reaction with acidic oxides: KOH reacts with acidic oxides (like CO_2 or SO_2) to form a salt and water. For example, with carbon dioxide (CO_2): 2KOH(aq) + CO_2(g) → K_2CO_3(aq) + H_2O(l) 3. Precipitation reactions with metal salts: KOH can react with solutions of certain metal salts to precipitate insoluble metal hydroxides. For example, with copper(II) sulfate (CuSO_4): 2KOH(aq) + CuSO_4(aq) → Cu(OH)_2(s) + K_2SO_4(aq) Here, copper(II) hydroxide (Cu(OH)_2) is an insoluble precipitate. That's 2 down. 3 left today — send the next one.