This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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Here are the short notes for each equation, including the reaction type and observations: a) 2KBr(aq) + Cl_2(g) 2KCl(aq) + Br_2(aq) Reaction Type: This is a displacement reaction (specifically, a halogen displacement) and a redox reaction*. Chlorine, being more reactive than bromine, displaces bromine from potassium bromide. Observations: The colorless potassium bromide solution reacts with yellowish-green chlorine gas. The solution turns orange-brown as bromine is formed. b) CuO(s) + H_2(g) Cu(s) + H_2O(l) Reaction Type: This is a redox reaction*. Hydrogen acts as a reducing agent, reducing black copper(II) oxide to pinkish-brown copper metal. Hydrogen itself is oxidized to water. Observations: Black solid copper(II) oxide turns into a pinkish-brown solid (copper metal). Colorless hydrogen gas is consumed, and colorless liquid water (or steam if heated) is produced. c) CH_2=CH_2(g) + H_2(g) CH_3CH_3(g) Reaction Type: This is an addition reaction, specifically hydrogenation*. Ethene (an alkene) reacts with hydrogen in the presence of a catalyst (e.g., nickel) to form ethane (an alkane). Observations: Both reactants (ethene and hydrogen) and the product (ethane) are colorless gases. There are no visible changes in color or state. The reaction typically requires heating and a catalyst. d) CH_3CH_2OH(aq) + CH_3COOH(aq) CH_3COOCH_2CH_3(aq) + H_2O(l) Reaction Type: This is an esterification reaction*. Ethanol (an alcohol) reacts with ethanoic acid (a carboxylic acid) to form ethyl ethanoate (an ester) and water. It is a reversible reaction, usually catalyzed by concentrated sulfuric acid. Observations: Both reactants are colorless liquids. The key observation is the formation of a new product, ethyl ethanoate, which has a characteristic sweet, fruity smell*. Send me the next one 📸