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Determine the relative reactivity of calcium and magnesium by observing their reactions with dilute hydrochloric acid.

Chemistry

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Practical Report: Determination of the Reactivity of Group 2 Metals

Title: WEEK 3 DETERMINATION OF THE REACTIVITY OF GROUP 2 METALS

Aim: To determine the relative reactivity of calcium and magnesium.

Apparatus and Materials:

  1. Test tube
  2. Test-tube rack
  3. Dilute hydrochloric acid
  4. Calcium
  5. Magnesium

Introduction:
Metals in Group 2 of the Periodic Table are less reactive than those in Group 1. This experiment indicates the relative reactivity of elements within the group.

Precaution:
Wear eye protection.

Procedure:

  1. Fill two test-tubes a quarter full with dilute hydrochloric acid.
  2. Into one test-tube drop a very small piece of magnesium.
  3. Into the other, drop a very small piece of calcium.
  4. Compare the reactivity of the two metals.
  5. Drop another bit of magnesium into the first test-tube and put your thumb over the end.
  6. When the pressure can be felt, take your thumb off and test the gas with a lighted splint.
  7. Record what happens.

Observation and Results:

Observation PointMagnesium + Dilute HClCalcium + Dilute HCl
Initial reactionSlow bubbling, magnesium slowly dissolves.Vigorous bubbling, calcium dissolves rapidly.
Heat changeSlight temperature increase.Significant temperature increase.
Gas test (Mg)Gas collected produces a 'pop' sound with a lighted splint.(Not tested in procedure, but would also be hydrogen)

Questions:

1. Which is the more reactive, magnesium or calcium?
Calcium is more reactive than magnesium.

2. Write word equations for these reactions.

  • Magnesium + Hydrochloric acid ⟶\longrightarrow Magnesium chloride + Hydrogen
  • Calcium + Hydrochloric acid ⟶\longrightarrow Calcium chloride + Hydrogen

3. Write formula equations for these reactions.

  • For Magnesium: Mg(s)+2HCl(aq)⟶MgCl2(aq)+H2(g)\text{Mg(s)} + 2\text{HCl(aq)} \longrightarrow \text{MgCl}_2\text{(aq)} + \text{H}_2\text{(g)}
  • For Calcium: Ca(s)+2HCl(aq)⟶CaCl2(aq)+H2(g)\text{Ca(s)} + 2\text{HCl(aq)} \longrightarrow \text{CaCl}_2\text{(aq)} + \text{H}_2\text{(g)}
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