Since the logarithms have the same base and are equal, their arguments must be equal.

April 2, 2026Chemistry

ScanSolve AI Answer

April 2, 2026

Answer

\log (b^2-4b)$

Here are the solutions to the logarithm equations:

13) $\log (16+2b) = \log (b^2-4b)$ Step 1: Since the logarithms have the same base and are equal, their arguments must be equal. $16+2b = b^2-4b$ Step 2: Rearrange the equation into a standard quadratic form. $b^2 - 4b - 2b - 16 = 0$ $b^2 - 6b - 16 = 0$ Step 3: Factor the quadratic equation. $(b-8)(b+2) = 0$ Step 4: Solve for $b$ .

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13) (16+2b) = (b^2-4b) Step 1: Since the logarithms have the same base and are equal, their arguments must be equal.

Asked on April 2, 2026Chemistry

This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.

ScanSolve AI AnswerAnswered on April 2, 2026

Here are the solutions to the logarithm equations: 13) (16+2b) = (b^2-4b) Step 1: Since the logarithms have the same base and are equal, their arguments must be equal. 16+2b = b^2-4b Step 2: Rearrange the equation into a standard quadratic form. b^2 - 4b - 2b - 16 = 0 b^2 - 6b - 16 = 0 Step 3: Factor the quadratic equation. (b-8)(b+2) = 0 Step 4: Solve for b.