We read your photo as:

Since the logarithms have the same base and are equal, their arguments must be equal.

April 2, 2026Chemistry

ScanSolve AI Answer

Step-by-step solution

4 steps

Here are the solutions to the logarithm equations:

13) $\log (16+2b) = \log (b^2-4b)$

Since the logarithms have the same base and are equal, their arguments must be equal.
$16+2b = b^2-4b$
Rearrange the equation into a standard quadratic form.
$b^2 - 4b - 2b - 16 = 0$ $b^2 - 6b - 16 = 0$
Factor the quadratic equation.
$(b-8)(b+2) = 0$
Solve for $b$ .

Was this helpful?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.