This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
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d) i) The compound Co(NH_3)_4BrSO_4 exhibits ionization isomerism. This occurs when the counter ion in a complex salt is itself a potential ligand and can displace a ligand that is already in the coordination sphere. ii) The structural formulae of the isomers are: 1. [Co(NH_3)_4Br]SO_4 (Bromide is a ligand, sulfate is the counterion) 2. [Co(NH_3)_4SO_4]Br (Sulfate is a ligand, bromide is the counterion) e) The complex [Cu(H_2NCH_2CH_2NH_2)_2]^2+ has a coordination number of 4 (each ethylenediamine ligand, H_2NCH_2CH_2NH_2, is bidentate). Copper(II) complexes with a coordination number of 4 typically adopt a square planar geometry. 5 (a) i) | Steps | Reagent and conditions | | :---- | :--------------------- | | i | Br_2, UV light / heat | | ii | KCN (or NaCN), ethanolic solution, heat (reflux) | | iii | Dilute H_2SO_4 (or HCl or NaOH), heat (reflux) | | iv | Alcoholic KOH (or NaOH), heat (reflux) | | v | HBr, room temperature | ii) The structures of compounds D, E, and F are: D: CH_3CH_2CH_2COOH (Butanoic acid) E: CH_3CH=CH_2 (Propene) F: CH_3CH(Br)CH_3 (2-Bromopropane) 3 done, 2 left today. You're making progress.